【leetcode】1450. Number of Students Doing Homework at a Given Time

题目如下：

Given two integer arrays startTime and endTime and given an integer queryTime.

The ith student started doing their homework at the time startTime[i] and finished it at time endTime[i].

Return the number of students doing their homework at time queryTime. More formally, return the number of students where queryTime lays in the interval [startTime[i], endTime[i]] inclusive.

Example 1:
Input: startTime = [1,2,3], endTime = [3,2,7], queryTime = 4
Output: 1
Explanation: We have 3 students where:
The first student started doing homework at time 1 and finished at time 3 and wasn't doing anything at time 4.
The second student started doing homework at time 2 and finished at time 2 and also wasn't doing anything at time 4.
The third student started doing homework at time 3 and finished at time 7 and was the only student doing homework at time 4.
Example 2:
Input: startTime = [4], endTime = [4], queryTime = 4
Output: 1
Explanation: The only student was doing their homework at the queryTime.
Example 3:
Input: startTime = [4], endTime = [4], queryTime = 5
Output: 0
Example 4:
Input: startTime = [1,1,1,1], endTime = [1,3,2,4], queryTime = 7
Output: 0
Example 5:
Input: startTime = [9,8,7,6,5,4,3,2,1], endTime = [10,10,10,10,10,10,10,10,10], queryTime = 5
Output: 5
Constraints:

startTime.length == endTime.length

1 <= startTime.length <= 100

1 <= startTime[i] <= endTime[i] <= 1000

1 <= queryTime <= 1000

解题思路：这也算题目？

代码如下：

class Solution(object):
    def busyStudent(self, startTime, endTime, queryTime):
        """
        :type startTime: List[int]
        :type endTime: List[int]
        :type queryTime: int
        :rtype: int
        """
        res = 0
        for start,end in zip(startTime,endTime):
            if queryTime >= start and queryTime <= end:
                res += 1
        return res