经典算法:n个人围成一圈,报m的离开,最后剩下谁?

public int remainPersonNumber(int n, int m) {
		//输入不合法
		if(n < 1 || m < 1)
			return -1;
		
		//初始化,存入List
		LinkedList<Integer> list = new LinkedList<>();
		for(int i = 0; i < n; i++) {
			list.add(i);
		}
		
		int index = 0;
		while(list.size() > 1) {
			index = (index + m - 1)%list.size();
			list.remove(index);
		}
		
		
		return list.get(0) + 1;
	}
原文地址:https://www.cnblogs.com/scuwangjun/p/8854327.html