Part1
+++
1.快排quick_sort()
分而治之
#include <iostream>
using namespace std;
const int N = 1e6 + 10;
int q[N], n;
void quick_sort(int q[], int l, int r)
{
if(l >= r) return;
int x = q[l + r >> 1], i = l - 1, j = r + 1;
while(i < j)
{
do i ++ ; while(q[i] < x);
do j -- ; while(q[j] > x);
if(i < j) swap(q[i], q[j]);
}
quick_sort(q, l, j);
quick_sort(q, j + 1, r);
}
int main()
{
scanf("%d", &n);
for(int i = 0; i < n; i ++ ) scanf("%d", q + i);
quick_sort(q, 0, n - 1);
for(int i = 0; i < n; i ++ ) printf("%d ", q[i]);
cout << endl;
return 0;
}
2.归并排序merge_sort()
#include <iostream>
using namespace std;
const int N = 1e6 + 10;
int q[N], temp[N], n;
void merge_sort(int q[], int l, int r)
{
if(l >= r) return;
int mid = l + r >> 1;
merge_sort(q, l, mid), merge_sort(q, mid + 1, r);
int k = 0, i = l, j = mid + 1;
while(i <= mid && j <= r)
if(q[i] <= q[j]) temp[k ++ ] = q[i ++ ];
else temp[k ++ ] = q[j ++ ];
while(i <= mid) temp[k ++ ] = q[i ++ ];
while(j <= r) temp[k ++ ] = q[j ++ ];
for(i = l, j = 0; i <= r; i ++ , j ++ ) q[i] = temp[j];
}
int main()
{
scanf("%d", &n);
for (int i = 0; i < n; i ++ ) scanf("%d", q + i);
merge_sort(q, 0, n - 1);
for (int i = 0; i < n; i ++ ) printf("%d ", q[i]);
cout << endl;
return 0;
}
3.高精度加法
(不压位)
#include <iostream>
#include <vector>
using namespace std;
vector<int> add(vector<int> &A, vector<int> &B)
{
vector<int> C;
int t = 0;
for(int i = 0; i < A.size() || i < B.size(); i ++ )
{
if(i < A.size()) t += A[i];
if(i < B.size()) t += B[i];
C.push_back(t % 10);
t /= 10;
}
if(t) C.push_back(1);
return C;
}
int main()
{
string a, b;
vector<int> A, B;
cin >> a >> b;
for (int i = a.size() - 1; i >= 0; i -- ) A.push_back(a[i] - '0');
for (int i = b.size() - 1; i >= 0; i -- ) B.push_back(b[i] - '0');
auto C = add(A, B);
for(int i = C.size() - 1; i >= 0; i -- ) printf("%d", C[i]);
return 0;
}
4.高精度减法
#include <iostream>
#include <vector>
using namespace std;
bool cmp(vector<int> &A, vector<int> &B)
{
if(A.size() != B.size()) return A.size() > B.size();
for(int i = A.size() - 1; i >= 0; i -- )
if(A[i] != B[i]) return A[i] > B[i];
return true;
}
vector<int> sub(vector<int> &A, vector<int> &B)
{
vector<int> C;
for(int i = 0, t = 0; i < A.size(); i ++ )
{
t = A[i] - t;
if(i < B.size()) t -= B[i];
C.push_back((t + 10) % 10);
if(t < 0) t = 1;
else t = 0;
}
while(C.size() > 1 && C.back() == 0) C.pop_back();//消除前置0
return C;
}
int main()
{
string a, b;
vector<int> A, B;
cin >> a >> b;
for(int i = a.size() - 1; i >= 0; i -- ) A.push_back(a[i] - '0');
for(int i = b.size() - 1; i >= 0; i -- ) B.push_back(b[i] - '0');
if(cmp(A, B))
{
auto C = sub(A, B);
for(int i = C.size() - 1; i >= 0; i -- ) printf("%d", C[i]);
}
else
{
auto C = sub(B, A);
printf("-");
for(int i = C.size() - 1; i >= 0; i -- ) printf("%d", C[i]);
}
return 0;
}
5.高精度乘法
#include <iostream>
#include <vector>
using namespace std;
vector<int> mul(vector<int> &A, int b)
{
vector<int> C;
for(int i = 0, t = 0; i < A.size() || t; i ++ )
{
if(i < A.size()) t += A[i] * b;
C.push_back(t % 10);
t /= 10;
}
while(C.size() > 1 && C.back() == 0) C.pop_back();
return C;
}
int main()
{
string a;
int b;
cin >> a >> b;
vector<int> A;
for(int i = a.size() - 1; i >= 0 ; i -- ) A.push_back(a[i] - '0');
auto C = mul(A, b);
for(int i = C.size() - 1; i >= 0; i -- ) printf("%d", C[i]);
return 0;
}
6.高精度除法
#include <iostream>
#include <algorithm>
#include <vector>
using namespace std;
vector<int> div(vector<int> &A, int b, int &r)
{
vector<int> C;
r = 0;
for(int i = A.size() - 1; i >= 0; i -- )
{
r = r * 10 + A[i];
C.push_back(r / b);
r %= b;
}
reverse(C.begin(), C.end());
while(C.size() > 1 && C.back() == 0) C.pop_back();
return C;
}
int main()
{
string a;
int b;
cin >> a >> b;
vector<int> A;
for(int i = a.size() - 1; i >= 0; i -- ) A.push_back(a[i] - '0');
int r;
auto C = div(A, b, r);
for(int i = C.size() - 1; i >= 0; i -- ) printf("%d", C[i]);
cout << endl << r << endl;
return 0;
}
7.前缀和
one way
#include <iostream>
using namespace std;
const int N = 1e5 + 10;
int a[N], s[N];
int main()
{
int n, m;
scanf("%d%d", &n, &m);
for (int i = 1; i <= n; i ++ )
{
scanf("%d", a + i);
s[i] = s[i - 1] + a[i];
}
int l, r;
while(m -- )
{
scanf("%d%d", &l, &r);
printf("%d
", s[r] - s[l - 1]);
}
return 0;
}
two way
#include <iostream>
using namespace std;
const int N = 1010;
int a[N][N], s[N][N];
int n, m, q;
int main()
{
scanf("%d%d%d", &n, &m, &q);
for (int i = 1; i <= n; i ++ )
for (int j = 1; j <= m; j ++ )
{
scanf("%d", &a[i][j]);
s[i][j] = s[i - 1][j] + s[i][j - 1] - s[i - 1][j - 1] + a[i][j];
}
int x1, y1, x2, y2;
while(q -- )
{
scanf("%d%d%d%d", &x1, &y1, &x2, &y2);
printf("%d
", s[x2][y2] - s[x2][y1 - 1] - s[x1 - 1][y2] + s[x1 - 1][y1 - 1]);
}
return 0;
}
8.差分
one way
#include <iostream>
using namespace std;
const int N = 1e5 + 10;
int a[N], b[N];
int n, m;
void insert(int l, int r, int c)
{
b[l] += c, b[r + 1] -= c;
}
int main()
{
scanf("%d%d", &n, &m);
for (int i = 1; i <= n; i ++ )
{
scanf("%d", a + i);
insert(i, i, a[i]);
}
int l, r, c;
while(m -- )
{
scanf("%d%d%d", &l, &r, &c);
insert(l, r, c);
}
for (int i = 1; i <= n; i ++ ) b[i] += b[i - 1];
for (int i = 1; i <= n; i ++ ) printf("%d ", b[i]);
return 0;
}
two way
#include <iostream>
using namespace std;
const int N = 1010;
int a[N][N], b[N][N];
int n, m, q;
void insert(int x1, int y1, int x2, int y2, int c)
{
b[x1][y1] += c;
b[x2 + 1][y1] -= c;
b[x1][y2 + 1] -= c;
b[x2 + 1][y2 + 1] += c;
}
int main()
{
scanf("%d%d%d", &n, &m, &q);
for (int i = 1; i <= n; i ++ )
for (int j = 1; j <= m; j ++ )
{
scanf("%d", &a[i][j]);
insert(i, j, i, j, a[i][j]);
}
int x1, x2, y1, y2, c;
while(q -- )
{
cin >> x1 >> y1 >> x2 >> y2 >> c;
insert(x1, y1, x2, y2, c);
}
for (int i = 1; i <= n; i ++ )
for (int j = 1; j <= m; j ++ )
b[i][j] += b[i - 1][j] + b[i][j - 1] - b[i - 1][j - 1];
for (int i = 1; i <= n; i ++ )
{
for(int j = 1; j <= m; j ++ )
printf("%d ", b[i][j]);
puts("");
}
return 0;
}
+++
+++
1.第k个数(quick_sort)
#include <iostream>
#include <algorithm>
using namespace std;
const int N = 1e5 + 10;
int a[N], n, k;
int quick_sort(int l, int r, int k)
{
if(l == r) return a[l];
int x = a[l + r >> 1], i = l - 1, j = r + 1;
while(i < j)
{
do i ++ ; while(a[i] < x);
do j -- ; while(a[j] > x);
if(i < j) swap(a[i], a[j]);
}
int sl = j - l + 1;
if(k <= sl) return quick_sort(l, j, k);
return quick_sort(j + 1, r, k - sl);
}
int main()
{
cin >> n >> k;
for (int i = 0; i < n; i ++ ) cin >> a[i];
cout << quick_sort(0, n - 1, k) << endl;
return 0;
}
2.逆序对的数量
#include <iostream>
using namespace std;
typedef long long LL;
const int N = 1e5 + 10;
int q[N], temp[N], n;
LL merge_sort(int l, int r)
{
if(l >= r) return 0;
int mid = l + r >> 1;
LL res = merge_sort(l, mid) + merge_sort(mid + 1, r);
int k = 0, i = l, j = mid + 1;
while(i <= mid && j <= r)
if(q[i] <= q[j]) temp[k ++ ] = q[i ++ ];
else
{
temp[k ++ ] = q[j ++ ];
res += mid - i + 1;
}
while(i <= mid) temp[k ++ ] = q[i ++ ];
while(j <= r) temp[k ++ ] = q[j ++ ];
for (i = l, j = 0; i <= r; i ++ , j ++ ) q[i] = temp[j];
return res;
}
int main()
{
scanf("%d", &n);
for (int i = 0; i < n; i ++ ) scanf("%d", q + i);
printf("%lld
", merge_sort(0, n - 1));
return 0;
}
+++
+++
9.双指针(最长连续不重复子序列)
先想暴力做法,然后根据单调关系优化复杂度
#include <iostream>
using namespace std;
const int N = 1e5 + 10;
int a[N], s[N], n;
int main()
{
scanf("%d", &n);
for (int i = 0; i < n; i ++ ) cin >> a[i];
int res = 0;
for (int i = 0, j = 0; i < n; i ++ )
{
s[a[i]] ++ ;
while(j <= i && s[a[i]] > 1)
{
s[a[j]] -- ;
j ++ ;
}
res = max(res, i - j + 1);
}
cout << res << endl;
return 0;
}
10.位运算(1的个数)
#include <iostream>
using namespace std;
int lowbit(int x)
{
return x & -x;
}
int main()
{
int n;
cin >> n;
while(n -- )
{
int x;
cin >> x;
int res = 0;
while(x) x -= lowbit(x), res ++ ;
cout << res << ' ';
}
return 0;
}
11.离散化(区间和)
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
typedef pair<int, int> PII;
const int N = 3e5 + 10;
int n, m;
int a[N], s[N];
vector<int> alls;
vector<PII> add, query;
int find(int x)
{
int l = 0, r = alls.size() - 1;
while(l < r)
{
int mid = l + r >> 1;
if(alls[mid] >= x) r = mid;
else l = mid + 1;
}
return r + 1;
}
int main()
{
cin >> n >> m;
int x, c;
for (int i = 0; i < n; i ++ )
{
cin >> x >> c;
add.push_back({x, c});
alls.push_back(x);
}
int l, r;
for (int i = 0; i < m; i ++ )
{
cin >> l >> r;
query.push_back({l, r});
alls.push_back(l);
alls.push_back(r);
}
//去重
sort(alls.begin(), alls.end());
alls.erase(unique(alls.begin(), alls.end()), alls.end());
for (auto item : add)
{
int x = find(item.first);
a[x] += item.second;
}
for (int i = 1; i <= alls.size(); i ++ ) s[i] = s[i - 1] + a[i];
for (auto item : query)
{
int l = find(item.first), r = find(item.second);
cout << s[r] - s[l - 1] << endl;
}
return 0;
}
12.区间和并
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
typedef pair<int, int> PII;
vector<PII> segs;
int n;
void merge(vector<PII> &segs)
{
vector<PII> res;
sort(segs.begin(), segs.end());
int st = -2e9, ed = -2e9;
for (auto seg : segs)
if(ed < seg.first)
{
if(ed != -2e9) res.push_back({st, ed});
st = seg.first, ed = seg.second;
}
else ed = max(ed, seg.second);
if(st != -2e9) res.push_back({st, ed});
segs = res;
}
int main()
{
scanf("%d", &n);
int l, r;
while(n -- )
{
scanf("%d%d", &l, &r);
segs.push_back({l, r});
}
merge(segs);
cout << segs.size() << endl;
return 0;
}