1002：
1002
1 #include<iostream> 2 #include<string> 3 using namespace std; 4 5 #define P(x) \ 6 cout << #x " " << x << ":" << endl; 7 8 #define PE(a, b, c, sum) \ 9 cout << a << " + " << b << " = " << (c ? "1" : "") << sum << endl; 10 int main() 11 { 12 int T; 13 cin >> T; 14 int Case = 1; 15 while(T--) 16 { 17 P(Case); 18 ++Case; 19 string a, b, sum; 20 cin >> a >> b; 21 //cout << a << " + " << b << " = " ; 22 int l_a = a.size()-1, l_b = b.size()-1, c = 0; 23 sum = (l_a > l_b ? a : b); 24 int i, j; 25 for(i = l_a, j = l_b; i >= 0 && j >= 0; --i, --j) 26 { 27 int s = a[i] - '0' + b[j] - '0' + c; 28 sum[i>j?i:j] = s % 10 + 48; 29 c = s / 10; 30 } 31 while(i >= 0) 32 { 33 int s = sum[i] - '0' + c; 34 sum[i] = s % 10 + 48; 35 c = s / 10; 36 i--; 37 } 38 while(j >= 0) 39 { 40 int s = sum[j] - '0' + c; 41 sum[j] = s % 10 + 48; 42 c = s / 10; 43 j--; 44 } 45 // cout << (c ? "1" : "") << sum << endl; 46 PE(a, b, c, sum); 47 if(T) 48 cout << endl; 49 } 50 return 0; 51 }
1042
1 #include<iostream> 2 #include<cstring> 3 using namespace std; 4 5 const int maxn = 40000; 6 int f[maxn]; 7 int main() 8 { 9 int n; 10 while(cin >> n) 11 { 12 memset(f, 0, sizeof(f)); 13 f[0] = 1; 14 for(int i = 2; i <= n; ++i) 15 { 16 //乘以i 17 int c = 0; 18 for(int j = 0; j < maxn; ++j) 19 { 20 int s = f[j] * i + c; 21 f[j] = s % 10; 22 c = s / 10; 23 } 24 } 25 int j; 26 for(j = maxn - 1; j >= 0 && !f[j]; --j); 27 for(int i = j; i >= 0; --i) 28 cout << f[i]; 29 cout << endl; 30 } 31 return 0; 32 }
1073：
View Code
1 #include<iostream> 2 #include<string> 3 #include<sstream> 4 using namespace std; 5 6 const int maxn = 1000; 7 8 void reverse(string &a) 9 { 10 string c = ""; 11 int len = a.size(); 12 for(int i = 0; i < len; ++i) 13 c += a[len-i-1]; 14 if(c == "") 15 c = "0"; 16 a = c; 17 } 18 19 //**********************去首部0************************** 20 void beg_0(string &a) 21 { 22 int beg = 0; 23 for(; beg < a.size() && a[beg] == '0'; ++beg); 24 if(beg < a.size()) 25 { 26 string t(a.begin()+beg,a.end()); 27 a = t; 28 } 29 else 30 a = "0"; 31 } 32 //**********************去末尾0************************** 33 void end_0(string& a) 34 { 35 int end = a.size()-1; 36 for(; end >=0 && a[end] == '0'; --end); 37 if(end >= 0) 38 { 39 string t(a.begin(), a.begin()+end+1); 40 a = t; 41 } 42 else 43 a = "0"; 44 } 45 //******************小数部分相加***************** 46 string de_add(string a, string b, int& d) 47 { 48 //传递小数部分向整数的的进位d 49 int x = a.size()-b.size(); 50 if(x < 0) 51 x = -x; 52 string c(x, '0'); 53 if(a.size() < b.size()) 54 a += c; 55 else if(b.size() < a.size()) 56 b += c; 57 reverse(a); 58 reverse(b); 59 if(a.size() < b.size()) 60 { 61 string c(b); 62 b = a; 63 a = c; 64 } 65 int i = 0; 66 d = 0; 67 while(i < b.size()) 68 { 69 a[i] = a[i] - '0' + b[i] - '0' + d; 70 d = a[i] / 10; 71 a[i] = a[i] % 10; 72 a[i] += '0'; 73 ++i; 74 } 75 while(i < a.size()) 76 { 77 a[i] =a[i] - '0' + d; 78 d = a[i] / 10; 79 a[i] %= 10; 80 a[i] += '0'; 81 ++i; 82 } 83 beg_0(a); 84 reverse(a); 85 return a; 86 } 87 //******************整数部分相加***************** 88 string in_add(string a, string b, int x) 89 { 90 reverse(a); 91 reverse(b); 92 if(a.size() < b.size()) 93 { 94 string c(b); 95 b = a; 96 a = c; 97 } 98 int i = 0, d = x; 99 while(i < b.size()) 100 { 101 a[i] = a[i] - '0' + b[i] - '0' + d; 102 d = a[i] / 10; 103 a[i] = a[i] % 10; 104 a[i] += '0'; 105 ++i; 106 } 107 while(i < a.size()) 108 { 109 a[i] =a[i] - '0' + d; 110 d = a[i] / 10; 111 a[i] %= 10; 112 a[i] += '0'; 113 ++i; 114 } 115 if(d) 116 a += '1'; 117 end_0(a); 118 reverse(a); 119 return a; 120 } 121 //*******************定位小数点********************** 122 int locate(string a) 123 { 124 int i; 125 for(i = 0; i < a.size() && a[i] != '.'; ++i); 126 return i; 127 } 128 int main() 129 { 130 string a, b; 131 while(cin >> a >> b) 132 { 133 //****************************分离小数部分和整数部分***************************** 134 string a1(a.begin(), a.begin()+locate(a)), a2 = "0"; 135 if(locate(a) != a.size()) 136 { 137 string t(a.begin()+locate(a)+1, a.end()); 138 a2 = t; 139 140 } 141 string b1(b.begin(), b.begin()+locate(b)), b2 = "0"; 142 if(locate(b) != b.size()) 143 { 144 string t(b.begin()+locate(b)+1, b.end()); 145 b2 = t; 146 } 147 //*****************************相加************************ 148 int d = 0; 149 string p = "", p_in = "", p_de = ""; 150 p_de = de_add(a2, b2, d); 151 p_in = in_add(a1, b1, d); 152 /******************************** 153 cout << p_in << endl; 154 cout << p_de << endl; 155 ************************************/ 156 p = p_in; 157 if(p_de != "0") 158 p += "." + p_de; 159 cout << p << endl; 160 } 161 return 0; 162 }
1316:万恶的读题啊，一下连续出错了三次，最后才发现是题目上的f2 = 2，不在是斐波那契数列了！！！
1316
1 #include<iostream> 2 #include<string> 3 #include<vector> 4 #include<cassert> 5 using namespace std; 6 7 const int maxn = 500 + 5; 8 void reverse(string& a) 9 { 10 string t = ""; 11 for(int i = a.size()-1; i >= 0; --i) 12 t += a[i]; 13 a = t; 14 } 15 //*******************重载加法操作符**************************** 16 string operator+(string a, string b) 17 { 18 reverse(a); 19 reverse(b); 20 int i = 0, c = 0; 21 if(a.size() < b.size()) 22 { 23 string t(b); 24 b = a; 25 a = t; 26 } 27 while(i < b.size()) 28 { 29 a[i] = a[i] - '0' + b[i] - '0' + c; 30 c = a[i] / 10; 31 a[i] %= 10; 32 a[i] += '0'; 33 ++i; 34 } 35 while(i < a.size()) 36 { 37 a[i] = a[i] - '0' + c; 38 c = a[i] / 10; 39 a[i] %= 10; 40 a[i] += '0'; 41 ++i; 42 } 43 if(c) 44 a += '1'; 45 reverse(a); 46 return a; 47 } 48 49 bool operator<(string a, string b) 50 { 51 if(a.size() != b.size()) 52 return a.size() < b.size(); 53 for(int i = 0; i < a.size(); ++i) 54 if(a[i] != b[i]) 55 return a[i] < b[i]; 56 return false; 57 } 58 bool operator >(string a, string b) 59 { 60 return b < a; 61 } 62 bool operator <=(string a, string b) 63 { 64 return !(a > b); 65 } 66 bool operator >=(string a, string b) 67 { 68 return !(a < b); 69 } 70 71 int main() 72 { 73 string str; 74 vector<string> svec; 75 string a0 = "0", a1 = "1", a2 = "2"; 76 svec.push_back(a0); 77 svec.push_back(a1); 78 svec.push_back(a2); 79 for(int i = 3; i < maxn; ++i) 80 { 81 str = "0"; 82 str = svec[i-1] + svec[i-2]; 83 svec.push_back(str); 84 } 85 /*********************************尝试容器上限范围******************************************** 86 int n; 87 while(cin >> n) 88 { 89 cout << svec[n] << endl; 90 } 91 *************************************************************************************************/ 92 string a, b; 93 while(cin >> a >> b, a != "0" || b != "0") 94 { 95 assert(a[0] != '-'); 96 assert(b[0] != '-'); 97 assert(a <= b); 98 /********************************************************************* 99 int c = 0, d; 100 string count = "0"; 101 for(int i = 1; i < svec.size(); ++i) 102 if(svec[i] >= a && svec[i] <= b) 103 { 104 reverse(count); 105 count[0] = count[0] - '0' + 1; 106 c = count[0] / 10; 107 count[0] %= 10; 108 count[0] += '0'; 109 //***************向前进位********************** 110 for(int i = 1; i < count.size() && c; ++i) 111 { 112 count[i] = count[i] - '0' + c; 113 c = count[i] / 10; 114 count[i] %= 10; 115 count[i] += '0'; 116 } 117 //*********************最终进位******************** 118 if(c) 119 count += '1'; 120 reverse(count); 121 } 122 ********************************************************************/ 123 int count = 0; 124 for(int i = 1; i < svec.size(); ++i) 125 if(svec[i] >= a && svec[i] <= b) 126 ++count; 127 cout << count << endl; 128 } 129 //************************************************************************/ 130 return 0; 131 }
1715
1 #include<iostream> 2 #include<string> 3 #include<vector> 4 using namespace std; 5 6 const int maxn = 1000 + 5; 7 8 void reverse(string& a) 9 { 10 string t = ""; 11 for(int i = a.size()-1; i >= 0; --i) 12 t += a[i]; 13 a = t; 14 } 15 string operator+(string a, string b) 16 { 17 reverse(a); 18 reverse(b); 19 int i = 0, c = 0; 20 if(a.size() < b.size()) 21 { 22 string t(b); 23 b = a; 24 a = t; 25 } 26 while(i < b.size()) 27 { 28 a[i] = a[i] - '0' + b[i] - '0' + c; 29 c = a[i] / 10; 30 a[i] %= 10; 31 a[i] += '0'; 32 ++i; 33 } 34 while(i < a.size()) 35 { 36 a[i] = a[i] - '0' + c; 37 c = a[i] / 10; 38 a[i] %= 10; 39 a[i] += '0'; 40 ++i; 41 } 42 if(c) 43 a += '1'; 44 reverse(a); 45 return a; 46 } 47 int main() 48 { 49 string str; 50 vector<string> svec; 51 string a0 = "0", a1 = "1", a2 = "1"; 52 svec.push_back(a0); 53 svec.push_back(a1); 54 svec.push_back(a2); 55 for(int i = 3; i < maxn; ++i) 56 { 57 str = "0"; 58 str = svec[i-1] + svec[i-2]; 59 svec.push_back(str); 60 } 61 int n, t; 62 cin >> t; 63 while(t--, cin >> n) 64 { 65 cout <<svec[n] << endl; 66 } 67 return 0; 68 }
1753
1 #include<iostream> 2 #include<string> 3 #include<sstream> 4 using namespace std; 5 6 const int maxn = 1000; 7 8 void reverse(string &a) 9 { 10 string c = ""; 11 int len = a.size(); 12 for(int i = 0; i < len; ++i) 13 c += a[len-i-1]; 14 if(c == "") 15 c = "0"; 16 a = c; 17 } 18 19 //**********************去首部0************************** 20 void beg_0(string &a) 21 { 22 int beg = 0; 23 for(; beg < a.size() && a[beg] == '0'; ++beg); 24 if(beg < a.size()) 25 { 26 string t(a.begin()+beg,a.end()); 27 a = t; 28 } 29 else 30 a = "0"; 31 } 32 //**********************去末尾0************************** 33 void end_0(string& a) 34 { 35 int end = a.size()-1; 36 for(; end >=0 && a[end] == '0'; --end); 37 if(end >= 0) 38 { 39 string t(a.begin(), a.begin()+end+1); 40 a = t; 41 } 42 else 43 a = "0"; 44 } 45 //******************小数部分相加***************** 46 string de_add(string a, string b, int& d) 47 { 48 //传递小数部分向整数的的进位d 49 int x = a.size()-b.size(); 50 if(x < 0) 51 x = -x; 52 string c(x, '0'); 53 if(a.size() < b.size()) 54 a += c; 55 else if(b.size() < a.size()) 56 b += c; 57 reverse(a); 58 reverse(b); 59 if(a.size() < b.size()) 60 { 61 string c(b); 62 b = a; 63 a = c; 64 } 65 int i = 0; 66 d = 0; 67 while(i < b.size()) 68 { 69 a[i] = a[i] - '0' + b[i] - '0' + d; 70 d = a[i] / 10; 71 a[i] = a[i] % 10; 72 a[i] += '0'; 73 ++i; 74 } 75 while(i < a.size()) 76 { 77 a[i] =a[i] - '0' + d; 78 d = a[i] / 10; 79 a[i] %= 10; 80 a[i] += '0'; 81 ++i; 82 } 83 beg_0(a); 84 reverse(a); 85 return a; 86 } 87 //******************整数部分相加***************** 88 string in_add(string a, string b, int x) 89 { 90 reverse(a); 91 reverse(b); 92 if(a.size() < b.size()) 93 { 94 string c(b); 95 b = a; 96 a = c; 97 } 98 int i = 0, d = x; 99 while(i < b.size()) 100 { 101 a[i] = a[i] - '0' + b[i] - '0' + d; 102 d = a[i] / 10; 103 a[i] = a[i] % 10; 104 a[i] += '0'; 105 ++i; 106 } 107 while(i < a.size()) 108 { 109 a[i] =a[i] - '0' + d; 110 d = a[i] / 10; 111 a[i] %= 10; 112 a[i] += '0'; 113 ++i; 114 } 115 if(d) 116 a += '1'; 117 end_0(a); 118 reverse(a); 119 return a; 120 } 121 //*******************定位小数点********************** 122 int locate(string a) 123 { 124 int i; 125 for(i = 0; i < a.size() && a[i] != '.'; ++i); 126 return i; 127 } 128 int main() 129 { 130 string a, b; 131 while(cin >> a >> b) 132 { 133 //****************************分离小数部分和整数部分***************************** 134 string a1(a.begin(), a.begin()+locate(a)), a2 = "0"; 135 if(locate(a) != a.size()) 136 { 137 string t(a.begin()+locate(a)+1, a.end()); 138 a2 = t; 139 140 } 141 string b1(b.begin(), b.begin()+locate(b)), b2 = "0"; 142 if(locate(b) != b.size()) 143 { 144 string t(b.begin()+locate(b)+1, b.end()); 145 b2 = t; 146 } 147 //*****************************相加************************ 148 int d = 0; 149 string p = "", p_in = "", p_de = ""; 150 p_de = de_add(a2, b2, d); 151 p_in = in_add(a1, b1, d); 152 /******************************** 153 cout << p_in << endl; 154 cout << p_de << endl; 155 ************************************/ 156 p = p_in; 157 if(p_de != "0") 158 p += "." + p_de; 159 cout << p << endl; 160 } 161 return 0; 162 } 163 164 /* 165 166 167 0000.326 00.2365 168 3 6 169 3.000 5.00000 170 8 9.4000 171 009 563.000 172 */
1047：（应该是无限循环了）
超时
1 #include<iostream> 2 #include<string> 3 using namespace std; 4 //读入到文件中，再从文件中每次读取一行，相加 5 string reverse(const string& a) 6 { 7 string t = ""; 8 for(int i = a.size()-1; i >= 0; --i) 9 t += a[i]; 10 return t; 11 } 12 13 string operator + (string a, string b) 14 { 15 a = reverse(a); 16 b = reverse(b); 17 int i = 0; 18 if(a.size() < b.size()) 19 { 20 string t(a); 21 a = b; 22 b = t; 23 } 24 int c = 0; 25 string result(a); 26 for(; i < b.size(); ++i) 27 { 28 result[i] = a[i] - '0' + b[i] - '0' + c; 29 c = result[i] / 10; 30 result[i] %= 10; 31 result[i] += '0'; 32 } 33 while(c && i < a.size()) 34 { 35 result[i] = result[i] - '0' + c; 36 c = result[i] / 10; 37 result[i] %= 10; 38 result[i] += '0'; 39 ++i; 40 } 41 if(c) 42 result += '1'; 43 result = reverse(result); 44 return result; 45 } 46 int main() 47 { 48 string str; 49 int n; 50 /************************************ 51 while(getline(cin, str) && str != "") 52 { 53 cout << ": " << str << endl; 54 } 55 ************************************/ 56 while(cin >> n, n != 0) 57 { 58 cin.ignore('\n');//忽略以后的空行 59 for(int i = 0; i < n; ++i) 60 { 61 string result = ""; 62 while(getline(cin, str) && str != "" && str != "0") 63 { 64 //遇到单独一个空行，输出结果 65 result =result + str; 66 } 67 cout << result << endl; 68 cout << endl; 69 } 70 } 71 return 0; 72 }
1047~正解
1 /*************************************** 2 万恶的前导零，本来以为整数就不会出现这种情 3 况的，还是不够谨慎啊 4 ***************************************/ 5 #include<iostream> 6 #include<string> 7 using namespace std; 8 9 string del_zero(string result) 10 { 11 int i = 0; 12 for(; i < result.size() && result[i] == '0'; ++i); 13 if(i == result.size()) 14 result = "0"; 15 else 16 { 17 string t(result.begin()+i, result.end()); 18 result = t; 19 } 20 return result; 21 } 22 string reverse(const string& a) 23 { 24 string t = ""; 25 for(int i = a.size()-1; i >= 0; --i) 26 t += a[i]; 27 return t; 28 } 29 30 string add(string a, string b) 31 { 32 a = reverse(a); 33 b = reverse(b); 34 int i = 0; 35 if(a.size() < b.size()) 36 { 37 string t(a); 38 a = b; 39 b = t; 40 } 41 int c = 0; 42 string result(a); 43 for(; i < b.size(); ++i) 44 { 45 result[i] = a[i] - '0' + b[i] - '0' + c; 46 c = result[i] / 10; 47 result[i] %= 10; 48 result[i] += '0'; 49 } 50 while(c && i < a.size()) 51 { 52 result[i] = result[i] - '0' + c; 53 c = result[i] / 10; 54 result[i] %= 10; 55 result[i] += '0'; 56 ++i; 57 } 58 if(c) 59 result += '1'; 60 result = reverse(result); 61 return result; 62 } 63 int main() 64 { 65 string str; 66 int n; 67 cin >> n; 68 for(int i = 0; i < n; ++i) 69 { 70 string result = ""; 71 while(getline(cin, str) && str != "0") 72 { 73 //遇到单独一个空行，输出结果 74 str = del_zero(str); 75 result = add(str, result); 76 } 77 cout << del_zero(result); 78 cout << ((i == n-1)?"\n":"\n\n"); 79 } 80 return 0; 81 }
1 #include<iostream> 2 #include<vector> 3 #include<string> 4 using namespace std; 5 6 //***************转换成整数************************** 7 inline bool is_decimals(const string& a) 8 { 9 int i = a.size()-1; 10 for(; i >= 0 && a[i] != '.'; --i); 11 if(i != -1) 12 return true; 13 return false; 14 } 15 inline string del_f_zero(string& a) 16 { 17 int i = 0; 18 for(; a[i] == '0' && i != a.size(); ++i); 19 if(i == a.size()) 20 a = "0"; 21 else 22 { 23 string b(a.begin()+i, a.end()); 24 a = b; 25 } 26 return a; 27 } 28 inline string del_l_zero(string& a) 29 { 30 //去除末尾零 31 int i = a.size()-1; 32 for(; i >= 0 && a[i] == '0' && a[i] != '.'; --i); 33 if(i != -1) 34 { 35 string t(a.begin(), a.begin()+i+1); 36 a = t; 37 } 38 else 39 a = "0"; 40 return a; 41 } 42 inline string del_point(string& a) 43 { 44 //000.00 45 if(a == ".") 46 return "0"; 47 if(a[0] == '.') 48 { 49 //0.300 50 string t(a.begin()+1, a.end()); 51 return t; 52 } 53 if(a[a.size()-1] == '.') 54 { 55 //3.000 56 string t(a.begin(), a.end()-1); 57 return t; 58 } 59 int i = 0; 60 for(; i < a.size() && a[i] != '.'; ++i); 61 if(i != a.size()) 62 { 63 string a_int(a.begin(), a.begin() + i); 64 string a_float(a.begin()+i+1, a.end()); 65 a = a_int + a_float; 66 } 67 return a; 68 } 69 inline int point(string& a) 70 { 71 //小数的位数 72 int i = a.size()-1; 73 for(; i >= 0 && a[i] == '0'; --i); 74 int j = 0; 75 for(; j < a.size() && a[j] != '.'; ++j); 76 return i - j; 77 } 78 inline string exchange(string& a) 79 { 80 a = del_f_zero(a);//去除前导零 81 if(is_decimals(a)) 82 { 83 a = del_l_zero(a);//如果是小数的话，去除末尾零 84 a = del_point(a);//去除小数点 85 } 86 return a; 87 } 88 89 inline string add_point(string& a, int p) 90 { 91 if(p > a.size()) 92 { 93 //0.0003 94 string zero(p-a.size(),'0'); 95 a = "." + zero + a; 96 } 97 else 98 { 99 p = a.size()-p; 100 string t1(a.begin(),a.begin()+p); 101 string t2(a.begin()+p, a.end()); 102 a = t1 + "." + t2; 103 } 104 if(a[0] == '.') 105 a = "0" + a; 106 return a; 107 } 108 inline string reverse(const string& a) 109 { 110 string t(a.rbegin(), a.rend()); 111 return t; 112 } 113 //***************整数部分运算************************** 114 115 inline string add(vector<string>& svec) 116 { 117 int j = svec.size()-1, i; 118 string result(svec[j]); 119 --j; 120 while(j >= 0) 121 { 122 result = reverse(result); 123 svec[j] = reverse(svec[j]); 124 int c = 0; 125 for(i = 0; i < svec[j].size(); ++i) 126 { 127 result[i] = result[i] - '0' + svec[j][i] - '0' + c; 128 c = result[i] / 10; 129 result[i] %= 10; 130 result[i] += '0'; 131 } 132 while(c && i < result.size()) 133 { 134 result[i] = result[i] - '0' + c; 135 c = result[i] / 10; 136 result[i] %= 10; 137 result[i] += '0'; 138 ++i; 139 } 140 if(c) 141 result += '1'; 142 result = reverse(result); 143 --j; 144 } 145 return result; 146 } 147 inline string power(string& a, int n) 148 { 149 if(a == "0") 150 return "0"; 151 string final(a); 152 a = reverse(a); 153 for(int i_case = 2; i_case <= n; ++i_case) 154 { 155 int j = 0; 156 vector<string> svec; 157 while(j < a.size()) 158 { 159 string result(final); 160 result = reverse(result); 161 int c = 0; 162 for(int i = 0; i < result.size(); ++i) 163 { 164 result[i] = (result[i] - '0')*(a[j] - '0') + c; 165 c = result[i] / 10; 166 result[i] %= 10; 167 result[i] += '0'; 168 } 169 if(c) 170 result += c + '0'; 171 string zero(j, '0'); 172 result = reverse(result); 173 result += zero;//对应位末尾加零 174 svec.push_back(result); 175 ++j; 176 } 177 final = add(svec);//更新每次结果 178 } 179 return final; 180 } 181 //*******************主函数**************************** 182 int main() 183 { 184 string a; 185 int n; 186 ios::sync_with_stdio(false); 187 while(cin >> a >> n) 188 { 189 int p = 0; 190 //cout << "point: " << p << endl; 191 if(is_decimals(a))//如果是小数的话，转换成整数，并传递小数的位数 192 { 193 p = point(a); 194 //cout << "p: " << p << endl; 195 } 196 a = exchange(a); 197 //cout << "exchange: " << a << endl; 198 a = power(a, n); 199 // cout << "power: " << a << endl; 200 p *= n; 201 //cout << "P: " << p << endl; 202 if(p) 203 a = add_point(a, p); 204 //cout << "add: " << a << endl; 205 if(a[0] == '0' && a[1] == '.') 206 { 207 string t(a.begin()+1, a.end()); 208 a = t; 209 } 210 cout << a << endl; 211 } 212 return 0; 213 } 214 215 /* 216 0 217 00.000 218 0.00 219 0.300 220 0.56000 221 00.0000300 222 223 224 0.000 10 225 3.12 10 226 0.003 3 227 228 229 */