给定一个字符串数组 words,找到 length(word[i]) * length(word[j]) 的最大值,并且这两个单词不含有公共字母。你可以认为每个单词只包含小写字母。如果不存在这样的两个单词,返回 0。
示例 1:
输入: ["abcw","baz","foo","bar","xtfn","abcdef"]
输出: 16
解释: 这两个单词为 "abcw", "xtfn"。
示例 2:
输入: ["a","ab","abc","d","cd","bcd","abcd"]
输出: 4
解释: 这两个单词为 "ab", "cd"。
示例 3:
输入: ["a","aa","aaa","aaaa"]
输出: 0
解释: 不存在这样的两个单词。
class Solution:
def maxProduct(self, words: List[str]) -> int:
word_dict = {}
for word in words:
word_dict[word] = 0
for c in word:
word_dict[word] |= 2**(ord(c)-97) ## 或运算、异或运算、与运算、按位取反运算
ans = 0
for i in range(len(words)-1):
for j in range(i+1,len(words)):
a = words[i]
b = words[j]
bit_a = word_dict[a]
bit_b = word_dict[b]
#print(i,j,a,b,bit_a,bit_b,bit_a&bit_b)
if bit_a&bit_b == 0:
ans = max(ans,len(a)*len(b))
return ans