Codility---MaxDoubleSliceSum

Task description

A non-empty zero-indexed array A consisting of N integers is given.

A triplet (X, Y, Z), such that 0 ≤ X < Y < Z < N, is called a double slice.

The sum of double slice (X, Y, Z) is the total of A[X + 1] + A[X + 2] + ... + A[Y − 1] + A[Y + 1] + A[Y + 2] + ... + A[Z − 1].

For example, array A such that:

A[0] = 3 A[1] = 2 A[2] = 6 A[3] = -1 A[4] = 4 A[5] = 5 A[6] = -1 A[7] = 2

contains the following example double slices:

  • double slice (0, 3, 6), sum is 2 + 6 + 4 + 5 = 17,
  • double slice (0, 3, 7), sum is 2 + 6 + 4 + 5 − 1 = 16,
  • double slice (3, 4, 5), sum is 0.

The goal is to find the maximal sum of any double slice.

Write a function:

class Solution { public int solution(int[] A); }

that, given a non-empty zero-indexed array A consisting of N integers, returns the maximal sum of any double slice.

For example, given:

A[0] = 3 A[1] = 2 A[2] = 6 A[3] = -1 A[4] = 4 A[5] = 5 A[6] = -1 A[7] = 2

the function should return 17, because no double slice of array A has a sum of greater than 17.

Assume that:

  • N is an integer within the range [3..100,000];
  • each element of array A is an integer within the range [−10,000..10,000].

Complexity:

  • expected worst-case time complexity is O(N);
  • expected worst-case space complexity is O(N), beyond input storage (not counting the storage required for input arguments).

Elements of input arrays can be modified.

Solution
 
Programming language used: Java
 
Code: 00:31:25 UTC, java, final, score:  100
// you can also use imports, for example:
// import java.util.*;

// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
import java.lang.Math;
class Solution {
    public int solution(int[] A) {
        // write your code in Java SE 8
        if(A.length < 4)
            return 0;
        int maxleft=0, maxending=0, maxslice=0;
        for(int i=3; i<A.length; i++) {
            maxleft = Math.max(maxleft+A[i-2], A[i-2]);
            maxending = Math.max(maxleft, Math.max( A[i-1], maxending+A[i-1]));
            maxslice = Math.max(maxending, maxslice);
        }
        return maxslice;
    }
}


https://codility.com/demo/results/trainingEJXAE5-H5P/
原文地址:https://www.cnblogs.com/samo/p/6991108.html