vijos p1449 字符串还原

学习<algorithm>下的reverse函数

#include<iostream>

#include<string>

#include<algorithm>

using namespace std;
int n;
bool judge(string s1, string s2, string s3) {
reverse(s1.begin(), s1.end());
bool flag = true;
for (int i = 0; i < n; i++)
{
if (((s2[i] - s1[i]) + (s3[i] - s1[i])) % 26 != 0)
{
flag = false;
break;
}
}
return flag;
}
int main()
{
cin >> n;
string s1, s2, s3;
cin >> s1 >> s2 >> s3;
if (judge(s1, s2, s3)) {
reverse(s1.begin(), s1.end()); cout << s1 << endl;
}
else if (judge(s2, s1, s3))
{
reverse(s2.begin(), s2.end()); cout << s2 << endl;
}
else if (judge(s3, s2, s1))
{
reverse(s3.begin(), s3.end()); cout << s3 << endl;
}
system("pause");
return 0;

原文地址:https://www.cnblogs.com/ruoh3kou/p/7661960.html