寻找旋转排序数组中的最小值

class Solution {
public:
    int findMin(vector<int>& nums) {
        if (nums.size() == 1) {
            return nums.front();
        }
        int left = 0; 
        int right = nums.size() - 1;

        if (nums[right] > nums.front()) {
            return nums.front();
        }

        while (left <= right) {
            int mid = (right - left) / 2 + left;
            if(nums[mid] > nums[mid + 1]) { // mid在折断点右侧
                return nums[mid + 1];
            }
            else if (nums[mid] < nums[mid - 1]) {
                return nums[mid];
            }
            
            if (nums[mid] < nums[0]){
                right = mid - 1;
            }
            else {
                left = mid + 1;
            }
        }
        return 0;// return nums[left] > nums.front() ? nums[left + 1] : nums[left];
    }
};

  

原文地址:https://www.cnblogs.com/rulin/p/13888622.html