zoj 1037 python

import sys
n = int(raw_input())

for i in range(1, n+1) :
    num = sys.stdin.readline()
    an = num.split()
    a = int(an[0])
    b = int(an[1])
    if(a%2) and (b%2) :
        sum = a * b + 0.41
    else :
        sum = a * b
    print 'Scenario #%d:' % i
    print "%.2f\n" % sum
#include <iostream>
#include <cstdio>
using namespace std;
int n, m;
int main() {
	int T;
	cin >> T;
	for(int i = 1; i <= T; i++) {
		cin >> n >> m;
		cout << "Scenario #" << i << ':' << endl;
		if(((n*m) & 1) == 0) {
			printf("%.2f\n", double(n * m));
		}
		else {
			printf("%.2f\n", 0.41 + n * m);
		}
		printf("\n");
	}
	return 0;
}
每天用一点时间去学一点新东西,淡定从容。在光束的路径上,进行长途的旅行,是不能着急的。

原文地址:https://www.cnblogs.com/robbychan/p/3786980.html