编译原理第八次作业

1.设有 NFA M=( {0,1,2,3}, {a,b},f,0,{3} ),其中 f(0,a)={0,1}  f(0,b)={0}  f(1,b)={2}  f(2,b)={3}

 画出状态转换矩阵,状态转换图,并说明该NFA识别的是什么样的语言。

答:

该状态转换矩阵为:

 

a

b

0

0,1

0

1

Ø

2

2

Ø

3

3

Ø

Ø

该状态转换图为:

 

 识别的语言为:(aIb)*abb

2.NFA 确定化为 DFA

  2.1解决多值映射:子集法

  (1). 上述练习1的NFA

    该状态转换矩阵为:

 

 

a

b

0

{0}

{0,1}

{0}

1

{0,1}

{0,1}

{0,2}

2

{0,2}

{0,1}

{0,3}

3

{0,3}

{0,1}

{0}

    该状态转换图为:

  

  (2)

   该状态转换矩阵为:

 

 

0

1

0

{S}

{V,Q}

{U,Q}

1

{V,Q}

{Z,V}

{Q,U}

2

{Z,V}

{Z}

{Z}

3

{U,Q}

{V}

{Z,Q,U}

4

{Z,Q,U}

{Z,V}

{Z,Q,U}

5

{Z}

{Z}

{Z}

6

{V}

{Z}

Ø

 

 

 

 

 

 

 

 

 

 

 

 

 

 

   该状态转换图为:

  2.2.解决空弧:对初态和所有新状态求ε-闭包

  (1). 发给大家的图2

  

    该状态转换矩阵为:

 

 

0

1

2

0

ε{A}={ABC}

ε{A}={ABC}

ε{B}={BC}

ε{C}={C}

1

{BC}

Ø

ε{B}={BC}

ε{C}={C}

2

{C}

Ø

Ø

ε{C}={C}

   该状态转换图为:

   (2).P50图3.6

   该状态转换矩阵为:

 

 

a

b

0

ε{0}={0,1,2,4,7}

ε{3,8}={3,6,7,1,2,4,8}

ε{5}={5,6,7,1,2,4}

1

ε{1,2,3,4,6,7,8}

ε{3,8}={3,6,7,8,1,2,4}

ε{59}={5,6,7,1,2,4,9}

2

ε{1,2,4,5,6,7}

ε{3,8}={3,6,7,8,1,2,4}

ε{5}={1,2,4,5,6,7}

3

ε{1,2,4,5,6,7,9}

ε{3,8}={3,6,7,8,1,2,4}

ε{5,10}={5,6,7,1,2,4,10}

4

ε{1,2,4,5,6,7,10}

ε{3,8}={3,6,7,8,1,2,4}

ε{5}={1,2,4,5,6,7}

   该状态转换图为:

原文地址:https://www.cnblogs.com/renshenbenzuig/p/11779564.html