求两数之间的素数个数(求素数算法大全)

 1 1、这种易理解
 2 L1 = []
 3 count = 0
 4 for x in range(1, 100):
 5     n = 0
 6     for y in range(1, x + 1):
 7         if x % y == 0:
 8             n = n + 1
 9     if n == 2:
10         count +=1
11         L1.append(x)
12 print(L1)
13 print(count)
14 
15 2、计算 2-100 之间素数的个数,返回结果。格式化字符串,标准
16 
17 def primeNum(f):
18     def f1():
19         sum_pri = 0
20         for i in range(2,101):
21             for j in  range(2,i):
22                 if i % j == 0:
23                     break
24                 elif j == i - 1:
25                     sum_pri += 1
26         return f(sum_pri+1)
27     return f1
28 @primeNum
29 def f(p):
30     print("2-100之间共有{}个素数".format(p))
31 f()
原文地址:https://www.cnblogs.com/reaix/p/12262106.html