sqlserver结果集转为字符串

比如有语句select username from Employee
返回结果是：
username
张三
李四
王五
怎么输出一个字符串类似：
张三，李四，王五

答：

declare @s varchar(1000)
select @s=isnull(@s+',','')+username from Employee
select @s as username

--------------------------------------------------------------------------
--  Author : htl258(Tony)
--  Date   : 2010-03-31 00:38:11
--  Version:Microsoft SQL Server 2008 (RTM) - 10.0.1600.22 (Intel X86) 
--          Jul  9 2008 14:43:34 
--          Copyright (c) 1988-2008 Microsoft Corporation
--          Developer Edition on Windows NT 5.1 <X86> (Build 2600: Service Pack 2)
--------------------------------------------------------------------------
--> 生成测试数据表:Employee
 
IF NOT OBJECT_ID('[Employee]') IS NULL
    DROP TABLE [Employee]
GO
CREATE TABLE [Employee]([username] NVARCHAR(10))
INSERT [Employee]
SELECT N'张三' UNION ALL
SELECT N'李四' UNION ALL
SELECT N'王五'
GO
--SELECT * FROM [Employee]
 
-->SQL查询如下:
 
DECLARE @S VARCHAR(100)
SELECT @S=ISNULL(@S+',','')+[username] FROM [Employee]
PRINT @S
--RESULT:
--张三,李四,王五

另外一个

请教各位大大？如何将
'01,02,03,04' 转换为1列的结果集
01
02
03
04

/* 拆分字符串   
* */ 
--拆分单列+序号
--方法一：利用数字辅助表
if object_id('fn_SplitTSQL')is not null drop function  fn_SplitTSQL
GO
create FUNCTION dbo.fn_SplitTSQL
  (@s NVARCHAR(MAX), @split NCHAR(1)) RETURNS TABLE
AS
RETURN
  SELECT
    n - LEN(REPLACE(LEFT(array, n), @split, '')) + 1 AS rn,
    SUBSTRING(array, n,
      CHARINDEX(@split, array + @split, n) - n) AS col
  FROM (SELECT @s AS array) AS D
    JOIN dbo.Nums
      ON n <= LEN(array)
      AND SUBSTRING(@split + array, n, 1) = @split;
GO
 
--方法二：直接拆分
if object_id('f_split')is not null drop function  f_split
go
create function f_split
(
@s     varchar(8000),  --待分拆的字符串
@split varchar(10)     --数据分隔符
)returns table
as
 return
 (
  select Row_number()over(order by Number) rn ,
  substring(@s,number,charindex(@split,@s+@split,number)-number)as col
  from master..spt_values
  where type='p' and number<=len(@s+'a') 
  and charindex(@split,@split+@s,number)=number
  )
go
 
select * from dbo.f_split('11,2,3',',')
select * from dbo.fn_SplitTSQL('11,2,3',',')
GO
 
--拆分多列
if object_id('fn_MutiSplitTSQL')is not null drop function  fn_MutiSplitTSQL
GO
create FUNCTION dbo.fn_MutiSplitTSQL  
  (@s NVARCHAR(MAX), @split NCHAR(1) ,@Sub@split NCHAR(1)= N',') RETURNS TABLE  
AS  
RETURN
  select * from (SELECT d.rn ,'col'+ cast( n - LEN(REPLACE(LEFT(col, n), @Sub@split, '')) + 1 as varchar(10)) AS attribute,  
    SUBSTRING(col, n, CHARINDEX(@Sub@split, col + @Sub@split, n) - n) AS value  
  FROM (  SELECT  n - LEN(REPLACE(LEFT(array, n), @split, '')) + 1 AS rn,  
    SUBSTRING(array, n, CHARINDEX(@split, array + @split, n) - n) AS col  
  FROM (SELECT @s AS array) AS D  
    JOIN dbo.Nums a 
      ON n <= LEN(array)  
     AND SUBSTRING(@split + array, n, 1) = @split ) AS D  
    JOIN dbo.Nums a 
      ON n <= LEN(col)  
     AND SUBSTRING(@Sub@split + col, n, 1) = @Sub@split ) as d
    PIVOT(max(value) FOR attribute 
                        IN(col1,col2 ,col3,col4,col5 )) AS P  
GO
 
 select col1,col2,col3,col4
    from dbo.fn_MutiSplitTSQL
    ('$092-1350,099201-080901,12050720,2012-6-11$092-0970,099204-072301,12050734,2012-6-11$','$',',')   
GO

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