123. Best Time to Buy and Sell Stock III

欢迎fork and star:Nowcoder-Repository-github

123. Best Time to Buy and Sell Stock III

题目

Say you have an array for which the ith element is the price of a given stock on day i.

Design an algorithm to find the maximum profit. You may complete at most two transactions.

Note:
You may not engage in multiple transactions at the same time (ie, you must sell the stock before you buy again).

解析

//Buy and Sell Stock iii
class Solution_123 {
public:
	int maxProfit(vector<int> &prices) {

		//1.买一次相当于减一个数,
		//2.买卖两次维持当前最大的收益

		int buy1 = INT_MIN, sell1 = 0;
		int buy2 = INT_MIN, sell2 = 0;

		for (int i = 0; i < prices.size();i++)
		{
			buy1 = max(buy1, -prices[i]);
			sell1 = max(sell1, buy1 + prices[i]); //一次买卖现有的收益

			buy2 = max(buy2, sell1 - prices[i]); //又要使用一些钱
			sell2 = max(sell2, buy2 + prices[i]);
		}
		return sell2;
	}
};

原文地址:https://www.cnblogs.com/ranjiewen/p/8194166.html