poj1528

简单题

View Code
#include<iostream>
#include<iomanip>
#include<cmath>
#include<string>
using namespace std;
char level[3][20]={"DEFICIENT","PERFECT","ABUNDANT"};
char a[1000];
void output(int n)
{
    int i;
    int mid=n/2;
    int sum=1;
    for(i=2;i<=mid;i++)
    {
        if(n%i==0)
        {
            sum+=i;
        }
    }
    if(sum<n)
        cout<<setw(5)<<n<<"  "<<level[0]<<endl;
    else if(sum==n)
        cout<<setw(5)<<n<<"  "<<level[1]<<endl;
    else cout<<setw(5)<<n<<"  "<<level[2]<<endl;
}


int main()
{
    int i,j;
    int N;
    int cur;
    cout<<"PERFECTION OUTPUT"<<endl;
    while(cin>>cur&&cur!=0)
    {
        
        if(cur==0)
            break;
        if(cur==1)
        {
            cout<<setw(5)<<cur<<"  "<<level[0]<<endl;
        }
        else
            output(cur);
    }
    cout<<"END OF OUTPUT"<<endl;
    return 0;
}
原文地址:https://www.cnblogs.com/rainydays/p/2866328.html