poj1974

简单题

View Code
#include <iostream>
#include
<cstdio>
#include
<cstdlib>
#include
<cstring>
#include
<algorithm>
using namespace std;

#define maxp 140000

struct Stone
{
int x, y;
}stone[maxp];

int n, m, p;
int ans;
bool vis[maxp];

bool operator < (const Stone &a, const Stone &b)
{
if (a.x != b.x)
return a.x < b.x;
return a.y < b.y;
}

int cal(int a)
{
if (a > 1)
return 1;
return 0;
}

void input()
{
scanf(
"%d%d%d", &n, &m, &p);
for (int i = 0; i < p; i++)
scanf(
"%d%d", &stone[i].x, &stone[i].y);
}

void work()
{
int pos = 0;
memset(vis,
0, sizeof(vis));
for (int i = 0; i < p - 1; i++)
{
ans
+= cal(stone[i].y - pos - 1);
pos
= stone[i].y;
if (stone[i].x != stone[i + 1].x)
{
ans
+= cal(m - stone[i].y);
pos
= 0;
}
vis[stone[i].x]
= true;
}
ans
+= cal(stone[p - 1].y - pos - 1);
ans
+= cal(m - stone[p - 1].y);
vis[stone[p
- 1].x] = true;
for (int i = 1; i <= n; i++)
if (!vis[i])
ans
+= cal(m);
}

int main()
{
//freopen("t.txt", "r", stdin);
int t;
scanf(
"%d", &t);
while (t--)
{
input();
if (n == 1 && m == 1)
{
printf(
"0\n");
continue;
}
if (p == 0)
{
printf(
"%d\n", cal(n) * m + cal(m) * n);
continue;
}
sort(stone, stone
+ p);
ans
= 0;
work();
swap(n, m);
for (int i = 0; i < p; i++)
swap(stone[i].x, stone[i].y);
sort(stone, stone
+ p);
work();
printf(
"%d\n", ans);
}
return 0;
}
原文地址:https://www.cnblogs.com/rainydays/p/2131346.html