poj2945

用为操作把串压缩为longlong。然后排序。

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <algorithm>
using namespace std;

#define maxn 20005

int n, m;
long long f[maxn];
int id[300];
int ans[maxn];

void input()
{
    getchar();
    for (int i = 0; i < n; i++)
    {
        f[i] = 0;
        for (int j = 0; j < m; j++)
        {
            char ch = getchar();
            f[i] <<= 2;
            f[i] += id[(int)ch];
        }
        getchar();
    }
}

void work()
{
    memset(ans, 0, sizeof(ans));
    int len = 1;
    for (int i = 1; i < n; i++)
        if (f[i] != f[i - 1])
        {
            ans[len]++;
            len = 1;
        }
        else
            len++;
    ans[len]++;
    for (int i = 1; i <= n; i++)
        printf("%d\n", ans[i]);
}

int main()
{
    //freopen("t.txt", "r", stdin);
    id[(int) 'A'] = 0;
    id[(int) 'T'] = 1;
    id[(int) 'C'] = 2;
    id[(int) 'G'] = 3;
    while (scanf("%d%d", &n, &m), n | m)
    {
        input();
        sort(f, f + n);
        work();
    }
    return 0;
}