poj3723

最小生成树,稀疏图用kruskal,O(ElogE)

View Code
#include <iostream>
#include
<cstdio>
#include
<cstdlib>
#include
<cstring>
#include
<algorithm>
using namespace std;

#define maxr 50005
#define maxn 20005

struct Edge
{
int u, v, w;
} edge[maxr];

int father[maxn];
int n, m, r;
int ans;

bool operator < (const Edge &a, const Edge &b)
{
return a.w > b.w;
}

int getanc(int a)
{
if (father[a] == a)
return a;
return father[a] = getanc(father[a]);
}

void merge(int a, int b)
{
father[getanc(a)]
= getanc(b);
}

void input()
{
scanf(
"%d%d%d", &n, &m, &r);
for (int i = 0; i < r; i++)
{
scanf(
"%d%d%d", &edge[i].u, &edge[i].v, &edge[i].w);
edge[i].v
+= n;
}
}

void work()
{
ans
= 0;
for (int i = 0; i < n + m; i++)
father[i]
= i;
for (int i = 0; i < r; i++)
{
if (getanc(edge[i].u) == getanc(edge[i].v))
continue;
merge(edge[i].u, edge[i].v);
ans
+= edge[i].w;
}
printf(
"%d\n", (n + m) * 10000 - ans);
}

int main()
{
//freopen("t.txt", "r", stdin);
int t;
scanf(
"%d", &t);
while (t--)
{
input();
sort(edge, edge
+ r);
work();
}
return 0;
}
原文地址:https://www.cnblogs.com/rainydays/p/2109485.html