poj1604

简单题

View Code
#include <iostream>
#include
<cstdio>
#include
<cstdlib>
#include
<cstring>
using namespace std;

int lastdigit(char *buf)
{
const int mod[20] =
{
1, 1, 2, 6, 4, 2, 2, 4, 2, 8, 4, 4, 8, 4, 6, 8, 8, 6, 8, 2 };
int len = strlen(buf), a[40], i, c, ret = 1;
if (len == 1)
return mod[buf[0] - '0'];
for (i = 0; i < len; i++)
a[i]
= buf[len - 1 - i] - '0';
for (; len; len -= !a[len - 1])
{
ret
= ret * mod[a[1] % 2 * 10 + a[0]] % 5;
for (c = 0, i = len - 1; i >= 0; i--)
c
= c * 10 + a[i], a[i] = c / 5, c %= 5;
}
return ret + ret % 2 * 5;
}

int main()
{
//freopen("t.txt", "r", stdin);
char st[10];
while (scanf("%s", st) != EOF)
printf(
"%5s -> %d\n", st, lastdigit(st));
return 0;
}

原文地址:https://www.cnblogs.com/rainydays/p/2081746.html