poj2583

简单题

View Code
#include <iostream>
#include
<cstdlib>
#include
<cstring>
#include
<cstdio>
using namespace std;

int main()
{
//freopen("D:\\t.txt", "r", stdin);
int c, abc, abc2, a, b;
while (scanf("%d%d%d", &c, &abc, &abc2)!= EOF)
{
a
= (abc2 - c - (abc - c) * 2) / 2;
b
= abc - a - c;
printf(
"%d %d %d\n", a * 9 + b * 3 + c, a * 16 + b * 4 + c, a * 25 + b * 5 + c);
}
return 0;
}
原文地址:https://www.cnblogs.com/rainydays/p/2033465.html