Remove Duplicates from Sorted List

题目:

Given a sorted linked list, delete all duplicates such that each element appear only once.

For example,
Given 1->1->2, return 1->2.
Given 1->1->2->3->3, return 1->2->3.

解析:

开始因为疏忽出现了两次runtime error情况,对于链表的问题一般就是如下情况

1. NULL->next

2. 指针是NULL,还用指针的val,p = NULL,p->val

 1 /**
 2  * Definition for singly-linked list.
 3  * struct ListNode {
 4  *     int val;
 5  *     ListNode *next;
 6  *     ListNode(int x) : val(x), next(NULL) {}
 7  * };
 8  */
 9 class Solution {
10 public:
11     ListNode* deleteDuplicates(ListNode* head) {
12         if(head == NULL || head->next == NULL)
13             return head;
14         ListNode *p = head;
15         while(p->next)
16         {
17             if(p->val == p->next->val)
18                 p->next = p->next->next;
19             else
20                 p = p->next;
21         }
22         return head;
23     }
24 };
原文地址:https://www.cnblogs.com/raichen/p/4999974.html