ACM练习：【ID1001】Easy or not？

Problem 1001

Easy or not

Time Limit: 1000ms
Memory Limit: 65536kb

Description

We are wondering how easy a problem can be. According to recent research, the most easy problem may be the one which requires to output exactly the input, other than the classical A+B Problem.
As our best programmer, you are asked to write a program to prove the conclusion.

Input

Lots of characters.

Output

Characters exactly the same as input.

Sample Input

The quick brown fox jumps over the lazy dog.
question = to ? be : !be;

Sample Output

The quick brown fox jumps over the lazy dog.
question = to ? be : !be;

Hint

Huge input

(1)

 1 #include<iostream>
 2 using namespace std;
 3 
 4 int main()
 5 {
 6     int c;
 7 
 8     while((c=getchar())!=EOF)
 9     {
10         putchar(c);
11     }
12         
13     return 0;
14 }

小结：解法(1)虽然实现了用例测试，根据编译信息，所使用的getchar()和putchar()函数在cstdio库中，并非iostream里，因此虽然VS可行，但online编译未通过。

(2)

更改头文件#include<iostream>为#include<cstdio>

注意如果把while((c=getchar())!=EOF)改为while((c=getchar())!='\n')，则是错误的答案，因为大量的文件输入，可能会中途换行。

 1 #include<cstdio>
 2 using namespace std;
 3 
 4 int main()
 5 {
 6     int c;
 7 
 8     while((c=getchar())!='EOF')
 9     {
10         putchar(c);
11     }
12         
13     return 0;
14 }

小结：这显然不是个好算法，耗时。

总结：有好的想法会继续更新。欢迎指正。