获取url的参数

首先设置公共函数

$.request = function (name) {
    var search = location.search.slice(1);
    var arr = search.split("&");
    for (var i = 0; i < arr.length; i++) {
        var ar = arr[i].split("=");
        if (ar[0] == name) {
            if (unescape(ar[1]) == 'undefined') {
                return "";
            } else {
                return unescape(ar[1]);
            }
        }
    }
    return "";
}

获取参数

var  aa = $.request("aa");

原文地址:https://www.cnblogs.com/quitpoison/p/10980333.html