Garage
题目连接：
http://codeforces.com/gym/100269/attachments
Description
Wow! What a lucky day! Your company has just won a social contract for building a garage complex.
Almost all formalities are done: contract payment is already transferred to your account.
So now it is the right time to read the contract. Okay, there is a sandlot in the form of W × H rectangle
and you have to place some garages there. Garages are w × h rectangles and their edges must be parallel
to the corresponding edges of the sandlot (you may not rotate garages, even by 90◦
). The coordinates of
garages may be non-integer.
You know that the economy must be economical, so you decided to place as few garages as possible.
Unfortunately, there is an opposite requirement in the contract: placing maximum possible number of
garages.
Now let’s see how these requirements are checked. . . The plan is accepted if it is impossible to add a new
garage without moving the other garages (the new garage must also have edges parallel to corresponding
sandlot edges).
Accepted optimal plan Rejected plan Accepted, but non-optimal plan
Time is money, find the minimal number of garages that must be ordered, so that you can place them
on the sandlot and there is no place for an extra garage.
Input
The only line contains four integers: W, H, w, h — dimensions of sandlot and garage in meters. You may
assume that 1 ≤ w ≤ W ≤ 30 000 and 1 ≤ h ≤ H ≤ 30 000.
Output
Output the optimal number of garages.
Sample Input
15 7 4 2
Sample Output
4
Hint
题意
现在给你一个矩形，W*H的，然后问你最少个w*h的小矩形
题解：
想一想
一个小矩形最多可以占据2*w*2*h的空间嘛
然后我们直接暴力算就好了，注意最后如果还有空位的话，就直接放一个进去就好了
代码
#include<bits/stdc++.h>
using namespace std;
int main()
{
freopen("garage.in","r",stdin);
freopen("garage.out","w",stdout);
long long W,H,w,h;
cin>>W>>H>>w>>h;
long long L,R,l,r;
L = W/w/2+W/w%2;
R = H/h/2+H/h%2;
cout<<L*R<<endl;
}