Codeforces Round #311 (Div. 2)B. Pasha and Tea 水题

B. Pasha and Tea

Time Limit: 20 Sec

Memory Limit: 256 MB

题目连接

http://codeforces.com/contest/557/problem/B

Description

Pasha decided to invite his friends to a tea party. For that occasion, he has a large teapot with the capacity of w milliliters and 2n tea cups, each cup is for one of Pasha's friends. The i-th cup can hold at most ai milliliters of water.

It turned out that among Pasha's friends there are exactly n boys and exactly n girls and all of them are going to come to the tea party. To please everyone, Pasha decided to pour the water for the tea as follows:

    Pasha can boil the teapot exactly once by pouring there at most w milliliters of water;
    Pasha pours the same amount of water to each girl;
    Pasha pours the same amount of water to each boy;
    if each girl gets x milliliters of water, then each boy gets 2x milliliters of water.

In the other words, each boy should get two times more water than each girl does.

Pasha is very kind and polite, so he wants to maximize the total amount of the water that he pours to his friends. Your task is to help him and determine the optimum distribution of cups between Pasha's friends.

Input

The first line of the input contains two integers, n and w (1 ≤ n ≤ 105, 1 ≤ w ≤ 109) — the number of Pasha's friends that are boys (equal to the number of Pasha's friends that are girls) and the capacity of Pasha's teapot in milliliters.

The second line of the input contains the sequence of integers ai (1 ≤ ai ≤ 109, 1 ≤ i ≤ 2n) — the capacities of Pasha's tea cups in milliliters.

Output

IPrint a single real number — the maximum total amount of water in milliliters that Pasha can pour to his friends without violating the given conditions. Your answer will be considered correct if its absolute or relative error doesn't exceed 10 - 6.

Sample Input

2 4
1 1 1 1

Sample Output

3

HINT

题意

给你n个女人和n个男人和w升茶

有2个操作

给所有男人倒同样大小的茶

给所有女人倒同样大小的茶

要求满足男人的茶至少是女人的2倍

问 最多倒多少茶?

题解:

排序贪心一下

具体看代码吧,很短,应该很好理解

代码

#include <cstdio>
#include <cmath>
#include <cstring>
#include <ctime>
#include <iostream>
#include <algorithm>
#include <set>
#include <vector>
#include <sstream>
#include <queue>
#include <typeinfo>
#include <fstream>
#include <map>
#include <stack>
typedef long long ll;
using namespace std;
//freopen("D.in","r",stdin);
//freopen("D.out","w",stdout);
#define sspeed ios_base::sync_with_stdio(0);cin.tie(0)
#define test freopen("test.txt","r",stdin)
#define maxn 300005
#define mod 10007
#define eps 1e-9
const int inf=0x3f3f3f3f;
const ll infll = 0x3f3f3f3f3f3f3f3fLL;
inline ll read()
{
    ll x=0,f=1;char ch=getchar();
    while(ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getchar();}
    while(ch>='0'&&ch<='9'){x=x*10+ch-'0';ch=getchar();}
    return x*f;
}
//**************************************************************************************

double a[maxn];
int main()
{
    int n=read(),w=read();
    for(int i=0;i<2*n;i++)
        scanf("%lf",&a[i]);
    sort(a,a+2*n);
    double mi=a[0],ma=a[n];
    double ans=min(mi,ma/2);
    ans=ans*3*n;
    ans=min(ans,w*1.0);
    printf("%.7f
",ans);
}
原文地址:https://www.cnblogs.com/qscqesze/p/4612212.html