List bean集合去除重复lambda 表达式 应用 stream（） 方式去重复,交集，并集

package ****,***,***;

import java.util.ArrayList;
import java.util.List;
import java.util.stream.Collectors;

import xxx.test.A;
import xxx.test.B;

/**
* 陈金玉
**/
public class Test {

    
    public static void main(String[] args) {
        List <A> aL=new ArrayList<A>();
        A a=new A();
        a.setAaa("aaa");
        a.setReq("reqaaa");
        a.setRes("resaaa");
        aL.add(a);
        A a1=new A();
        a1.setAaa("aaa1");
        a1.setReq("reqaaa1");
        a1.setRes("reqaaa1");
        aL.add(a1);
        
        List <B> bL=new ArrayList<B>();
        B b=new B();
        b.setFff("aaa");
        b.setGgg("f1");
        b.setRes("f2");
        bL.add(b);
        
        List<B> toList = bL.parallelStream().map( user ->{
            A user1 = aL.stream().filter(u ->!user.getFff().equals(u.getAaa())).findFirst().orElse(null);
            if(null != user1){
                user.setFff(user1.getAaa()); 
                user.setGgg(user1.getReq());
                user.setRes(user1.getRes());
            }
            return user;
        }).collect(Collectors.toList());
        
        for( B ttt:toList ) {
            System.out.println(ttt.getGgg());
            System.out.println(ttt.getRes());
            System.out.println(ttt.getFff());
            System.out.println("--------------");
        }
        
    }
}