hdu 1520 树形DP基础

http://acm.hdu.edu.cn/showproblem.php?pid=1520

父节点和子节点不能同时选。

http://blog.csdn.net/woshi250hua/article/details/7641589

首先是建树,这个在之前的树形背包里有讲:http://www.cnblogs.com/qlky/p/5650783.html

因为这里没有指定根节点,所以可以建双向边,这样就可以从任一个点出发遍历

接下来是DP,状态转移方程:

dp[fa][0] += max(dp[son][0]+dp[son][1])

dp[fa][1] += dp[son][0]

#include <iostream>
#include <string>
#include <cstring>
#include <cstdlib>
#include <cstdio>
#include <cmath>
#include <algorithm>
#include <stack>
#include <queue>
#include <cctype>
#include <vector>
#include <iterator>
#include <set>
#include <map>
#include <sstream>
using namespace std;

#define mem(a,b) memset(a,b,sizeof(a))
#define pf printf
#define sf scanf
#define spf sprintf
#define pb push_back
#define debug printf("!
")
#define MAXN 20000+5
#define MAX(a,b) a>b?a:b
#define blank pf("
")
#define LL long long
#define ALL(x) x.begin(),x.end()
#define INS(x) inserter(x,x.begin())
#define pqueue priority_queue
#define INF 0x3f3f3f3f

#define ls (rt<<1)
#define rs (rt<<1|1)

int n,m;

int ptr = 1,head[MAXN],a[MAXN],dp[MAXN][2],vis[MAXN];

struct node
{
    int y,val,next;
}tree[MAXN];

void add(int fa,int son)
{
    tree[ptr].y = son;
    tree[ptr].next = head[fa];
    head[fa] = ptr++;
}

void dfs(int root)
{
    vis[root] = 1;
    dp[root][1] = a[root];
    dp[root][0] = 0;
    for(int i=head[root];i!=-1;i=tree[i].next)
    {
        int y = tree[i].y;
        if(vis[y]) continue;
        dfs(tree[i].y);
        dp[root][0] += max(dp[y][0],dp[y][1]);
        dp[root][1] += dp[y][0];
    }
}

int main()
{
    int i,j,t,kase=1;
    while(~sf("%d",&n))
    {
        mem(a,0);
        mem(vis,0);
        mem(dp,0);
        mem(head,-1);
        ptr = 1;
        for(i=1;i<=n;i++) sf("%d",&a[i]);
        int x,y;
        while(sf("%d%d",&x,&y),x+y)
        {
            add(y,x);
            add(x,y);
        }
        dfs(1);
        pf("%d
",max(dp[1][0],dp[1][1]));

    }
    return 0;
}
原文地址:https://www.cnblogs.com/qlky/p/5769297.html