mongodb查询后排序

var user = db.getCollection('user')

//user.find({},{_id:0}).pretty().count()

user.find({age:{$gte:25,$lt:70}},{_id:-1})

.sort({age:-1})

.skip(2).limit(2)

.pretty()

原文地址:https://www.cnblogs.com/qiyc/p/8746067.html