有进度条的圆周率计算

 1 from random import random
 2 import time
 3 from time import perf_counter
 4 darts=10000*10000
 5 hits=0.0
 6 scale=10
 7 start=perf_counter()
 8 for j in range(scale+1):
 9     a='*'*j
10     b='.'*(scale-j)
11     c=(j/scale)*100
12     dur=time.perf_counter()-start
13     print("{:^3.0f}%[{}->{}]{:.2f}s".format(c,a,b,dur))
14     time.sleep(0.1)
15 for i in range(1,darts+1):
16     x,y=random(),random()
17     dist=pow(x**2+y**2,0.5)
18     if dist<=1.0:
19         hits=hits+1 
20     pi=4*(hits/darts)
21 print("/n"+"圆周率的值是{}".format(pi))