Python算法-二叉树深度优先遍历

二叉树

组成:

1、根节点  BinaryTreeroot

2、每一个节点,都有左子节点和右子节点(可以为空)  TreeNodevalueleftright

二叉树的遍历:

遍历二叉树:深度优先遍历、广度优先遍历。

 

广度:先遍历兄弟节点,再遍历子节点    

深度:先遍历子节点,再遍历兄弟节点

上图深度遍历结果:50/20/60/15/30/70

上图广度遍历结果:50/20/15/30/60/70

深度遍历又分为先序、中序、后序的遍历方式:

先序遍历:先根节点,再左子树,再右子树

上图先序遍历结果:50/20/ 15/ 30/ 60/ 70

中序遍历:先左子树,再根节点,再右子树

上图中序遍历结果:15/20/30/50/60/70

后序遍历:先左子树,再右子树,再根节点

上图后序遍历结果:15/30/20/70/60/50

代码实现:

# encoding=utf-8

class TreeNode(object): #定义二叉树类

    def __init__(self,val,left=None,right=None):

        self.val = val

        self.left = left

        self.right = right

class BinaryTree(object):

    def __init__(self,root=None):

        self.root = root

    def preScan(self,retList, node): #先序遍历:先跟、再左、后右

        if node != None:

            retList.append(node.val)

            self.preScan(retList, node.left)

            self.preScan(retList, node.right)

        return retList

    def midScan(self, retList, node): #中序遍历:先左、再跟、后右

        if node != None:

            self.midScan(retList, node.left)

            retList.append(node.val)

            self.midScan(retList, node.right)

        return retList

    def postScan(self, retList, node): #后序遍历:先左、再右、后跟

        if node != None:

            self.postScan(retList, node.left)

            self.postScan(retList, node.right)

            retList.append(node.val)

        return retList

if __name__ =='__main__':

    root = TreeNode(50)

    root.left = TreeNode(20,left=TreeNode(15),right=TreeNode(30,right=TreeNode(12)))

    root.right = TreeNode(60,right=TreeNode(70))

bTree = BinaryTree(root)

retList = bTree.preScan([],bTree.root)

print retList

retList2 = bTree.midScan([],bTree.root)

print retList2

retList3 = bTree.postScan([],bTree.root)

print retList3

原文地址:https://www.cnblogs.com/qingqing-919/p/8542501.html