集合和深浅copy #

集合:可变的数据类型,他里面的元素必须是不可变的数据类型,无序,不重复。

# set1 = set({1,2,3})
# set2 = {1,2,3,[2,3],{'name':'alex'}} # 错的
# print(set1)
# print(set2)
# set1 = {'alex','wusir','ritian','egon','barry',}
#增
#add
# set1.add('女神')
# print(set1)
#update
# set1.update('abc')
# print(set1)
#删除

# set1.pop() # 随机删除
# print(set1.pop()) # 有返回值
# print(set1)

# set1.remove('alex') # 按元素
# print(set1)

#{} set()
# set1.clear()
# print(set1) # set()

# del set1
# print(set1)

#查
# for i in set1:
# print(i)

# set1 = {1,2,3,4,5}
# set2 = {4,5,6,7,8}
# set3 = set1 & set2
# print(set3) # {4, 5}
# print(set1.intersection(set2)) # {4, 5}

# set1 = {1,2,3,4,5}
# set2 = {4,5,6,7,8}
# print(set1 | set2) # {1, 2, 3, 4, 5, 6, 7,8}
# print(set2.union(set1)) # {1, 2, 3, 4, 5, 6, 7}

# set1 = {1,2,3,4,5}
# set2 = {4,5,6,7,8}
# print(set1 ^ set2) # {1, 2, 3, 6, 7, 8}
# print(set1.symmetric_difference(set2)) # {1, 2, 3, 6, 7, 8}

# set1 = {1,2,3,4,5}
# set2 = {4,5,6,7,8}
# print(set1 - set2) # {1, 2, 3}
# #set1独有的
# print(set1.difference(set2)) # {1, 2, 3}

# set1 = {1,2,3,}
# set2 = {1,2,3,4,5,6}
#
# print(set1 < set2)
# print(set1.issubset(set2)) # 这两个相同,都是说明set1是set2子集。

# print(set2 > set1)
# print(set2.issuperset(set1)) # 这两个相同,都是说明set2是set1超集。


#去重
# li = [1,2,33,33,2,1,4,5,6,6]
# set1 = set(li)
# # print(set1)
# li = list(set1)
# print(li)
# s1 = {1,2,3}
# print(s1,type(s1))

# s = frozenset('barry')
# print(s,type(s))
# for i in s:
# print(i)

深浅copy

# 赋值运算
# l1 = [1,2,3]
# l2 = l1
# l1.append('a')
# print(l1,l2)

#copy
# l1 = [1,2,3]
# l2 = l1.copy()
# print(l1,l2)
# print(id(l1),id(l2))
# l2.append('a')
# print(l1,l2)

# l1 = [1,2,[4,5,6],3]
# l2 = l1.copy()

# print(l1,id(l1))
# print(l2,id(l2))
# l1.append('a')
# print(l1,l2)
# l1[2].append('a')
# print(l1,l2)
# print(id(l1[2]))
# print(id(l2[2]))
import copy
# l1 = [1,2,[4,5,6],3]
# l2 = copy.deepcopy(l1)
# print(l1,id(l1))
# print(l2,id(l2))
# l1[2].append('a')
# print(l1,l2)

# l1 = [1,[1],2,3,4]
# l2 = l1[:]
# l1[1].append('a')
#l2 的结果是什么?


# print(l1,id(l1))
# print(l2,id(l2))
# print(l1[1] is l2[1])

# li = ['alex','taibai','wusir','egon']
# for i in li:
# print(li.index(i),i)

# for index,i in enumerate(li,1):
# print(index,i)

原文地址:https://www.cnblogs.com/qinghuani/p/8110808.html