[leedcode 155] Min Stack

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.

  • push(x) -- Push element x onto stack.
  • pop() -- Removes the element on top of the stack.
  • top() -- Get the top element.
  • getMin() -- Retrieve the minimum element in the stack.
    class MinStack {
        //使用两个栈,一个正常使用,一个保存已经压栈中最小的数,每次push和pop注意两个栈同时操作
        private Stack<Integer> min=new Stack<Integer>();
        private Stack<Integer> stack=new Stack<Integer>();
        public void push(int x) {
            stack.push(x);
            if(min.empty()||x<min.peek()){//注意min判空
                min.push(x);
            }else{
                min.push(min.peek());
            }
        }
    
        public void pop() {
            stack.pop();
            min.pop();
            
        }
    
        public int top() {
            return stack.peek();
        }
    
        public int getMin() {
            return min.peek();
            
        }
    }
原文地址:https://www.cnblogs.com/qiaomu/p/4694797.html