[leedcode 114] Flatten Binary Tree to Linked List

Given a binary tree, flatten it to a linked list in-place.

For example,
Given

         1
        / 
       2   5
      /    
     3   4   6

The flattened tree should look like:

   1
    
     2
      
       3
        
         4
          
           5
            
             6

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
    public void flatten(TreeNode root) {
        //左节点赋值到右节点，右节点变成原左节点的最右边节点的右节点
/*        (1) 找到左节点最右的子节点
        (2) 保存右节点
        (3) 将原左节点放到右节点
        (4) 左节点置空
        (5) 原右节点变成原左节点的最右节点
        (6) 向下遍历，直到空节点*/
        if(root==null) return;
        TreeNode node=root;
       while(node!=null){
            if(node.left!=null){
            TreeNode right=node.left;
            while(right.right!=null){
                right=right.right;
            }
            TreeNode temp=node.right;
            node.right=node.left;
            node.left=null;
            right.right=temp;
            
            }
            node=node.right;
       }
    }
}