基于URL的正则匹配

第一种的方式使用(

<li><a  target="_blank"  href="/CC/detail/?nid={{ k}}">{{ row.name }}</a></li>

url(r'^detail/', views.detail),

http://127.0.0.1:8000/CC/detail/?nid=3

def detail(request):
    print '2222222222222',request.GET
    nid =request.GET.get("nid")
    detail_info = USER_DICT[nid]
    return render(request,'detail.html',{"dict":detail_info})

<ul>
    {% for k,row in user_dict.items %}
        <li><a  target="_blank"  href="/CC/detail/?nid={{ k}}">{{ row.name }}</a></li>
    {% endfor %}
</ul>

  

第二种方式:(

<li><a  target="_blank"  href="/CC/detail-{{ k}}.html">{{ row.name }}</a></li>

url(r'^detail-(d+).html', views.detail2),
http://127.0.0.1:8000/CC/detail-1.html

def detail2(request,nid):
    print '2222222222222',request.GET
    # nid =request.GET.get(nid)
    detail_info = USER_DICT[nid]
    return render(request,'detail.html',{"dict":detail_info})

<ul>
    {% for k,row in user_dict.items %}
        <li><a  target="_blank"  href="/CC/detail-{{ k}}.html">{{ row.name }}</a></li>
    {% endfor %}
</ul>

  

第三种方式,多个值的匹配:

url(r'^detail-(?P<nid>d+)-(?P<uid>d+).html', views.detail3),
def detail3(request,**kwargs):
    print kwargs
  

a. 
url(r'^detail-(d+)-(d+).html', views.detail),

def func(request, nid, uid):

pass

def func(request, *args):
args = (2,9)


def func(request, *args, **kwargs):
args = (2,9)

b. 
url(r'^detail-(?P<nid>d+)-(?P<uid>d+).html', views.detail)

def func(request, nid, uid):
pass

def funct(request, **kwargs):
kwargs = {'nid': 1, 'uid': 3}

def func(request, *args, **kwargs):
args = ()
kwargs = {'nid': 1, 'uid': 3}

原文地址:https://www.cnblogs.com/qiangayz/p/8971438.html