hdu 2062 Subset sequence

Subset sequence

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 4636    Accepted Submission(s): 2248


Problem Description
Consider the aggregate An= { 1, 2, …, n }. For example, A1={1}, A3={1,2,3}. A subset sequence is defined as a array of a non-empty subset. Sort all the subset sequece of An in lexicography order. Your task is to find the m-th one.
 
Input
The input contains several test cases. Each test case consists of two numbers n and m ( 0< n<= 20, 0< m<= the total number of the subset sequence of An ).
 
Output
For each test case, you should output the m-th subset sequence of An in one line.
 
Sample Input
1 1
2 1
2 2
2 3
2 4
3 10
 
Sample Output
1
1
1 2
2
2 1
2 3 1
 
Author
LL
 
Source
 
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附上代码:
 
 1 #include <iostream>
 2 #include <cstdio>
 3 using namespace std;
 4 int main()
 5 {
 6     int i,n,t;
 7     __int64 m,c[21]= {0};
 8     int s[21];
 9     for(i=1; i<21; i++)
10         c[i]=c[i-1]*(i-1)+1;
11     while(~scanf("%d%I64d",&n,&m))
12     {
13         for(i=0; i<21; i++)
14             s[i]=i;
15         while(n>0&&m>0)
16         {
17             t=m/c[n]+(m%c[n]>0?1:0);
18             if(t>0)
19             {
20                 printf("%d",s[t]);
21                 for(i=t; i<=n; i++)
22                     s[i]=s[i+1];
23                 m-=((t-1)*c[n]+1);
24                 if(m==0) printf("
");
25                 else printf(" ");
26             }
27             n--;
28         }
29     }
30     return 0;
31 }
原文地址:https://www.cnblogs.com/pshw/p/5333850.html