A simple problem
Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3866 Accepted Submission(s): 1444
Problem Description
Zty很痴迷数学问题.。一天,yifenfei出了个数学题想难倒他,让他回答1 / n。但Zty却回答不了^_^. 请大家编程帮助他.
Input
第一行整数T,表示测试组数。后面T行,每行一个整数 n (1<=|n|<=10^5).
Output
输出1/n. (是循环小数的,只输出第一个循环节).
Sample Input
4 2 3 7 168
Sample Output
0.5 0.3 0.142857 0.005952380
Author
yifenfei
Source
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/*其实这一道题跟一般的数学除法很像,只是真正的小数除法都是在小数点后边, 但是那样在c语言中是行不通的,所以每一步乘以10来计算,vis标记是否出现过*/ #include<stdio.h> #include<string.h> #define 100000+100 int vis[MAX]; int main() { int yu,t,n; scanf("%d",&t); while(t--) { scanf("%d",&n); if(n==1) { printf("1 "); continue; } if(n<0) { printf("-"); n=-n; } printf("0."); memset(vis,0,sizeof(vis)); yu=1,vis[1]=1; while(yu) { yu*=10; printf("%d",yu/10); yu%=10; if(vis[yu]) break; vis[yu]=1; } printf(" "); } return 0; }