leetcode------Remove Duplicates from Sorted Array II

标题:

Remove Duplicates from Sorted Array II

通过率: 30.7%
难度: 中等

ollow up for "Remove Duplicates":
What if duplicates are allowed at most twice?

For example,
Given sorted array A = [1,1,1,2,2,3],

Your function should return length = 5, and A is now [1,1,2,2,3].

做过第一个版本。就是去除重复的,用一个指针记录真实应该到哪个位置就行,

现在时做去除大于2的重复,依然与1一样,有个区别就是用一个标志位来判断是不是大于2就行

具体看代码:

 1 public class Solution {
 2     public int removeDuplicates(int[] A) {
 3         if(A.length==0) return 0;
 4         int index=1;
 5         int flag=0;
 6         for(int i=1;i<A.length;i++){
 7             if(A[i]!=A[i-1]){
 8                 A[index]=A[i];
 9                 index++;
10                 flag=0;
11             }
12             else if(A[i]==A[i-1]){
13                 if(flag!=2){
14                 A[index]=A[i];
15                 index++;
16                 flag=2;
17                 }
18             }
19         }
20         return index;
21     }
22 }
原文地址:https://www.cnblogs.com/pkuYang/p/4333971.html