leetcode------Reverse Words in a String

标题: Reverse Words in a String
通过率:  14.8%  
难度:   中等

Given an input string, reverse the string word by word.

For example,
Given s = "the sky is blue",
return "blue is sky the".

Update (2015-02-12):
For C programmers: Try to solve it in-place in O(1) space.

click to show clarification.

Clarification:
  • What constitutes a word?
    A sequence of non-space characters constitutes a word.
  • Could the input string contain leading or trailing spaces?
    Yes. However, your reversed string should not contain leading or trailing spaces.
  • How about multiple spaces between two words?
    Reduce them to a single space in the reversed string.
 
本本题思路比较清晰,就是遇到空格就是停止然后开始跳空格,最后进行迭代操作,具体代码如下:
 1 public class Solution {
 2     public String reverseWords(String s) {
 3            s = s.trim();
 4     return helper(s,0).toString();
 5         
 6     }
 7     private StringBuilder helper(String s, int index)
 8 {
 9     if(index>=s.length())
10         return new StringBuilder(); 
11     StringBuilder cur = new StringBuilder();
12     int lastIndex = index;
13     while(index < s.length() && s.charAt(index)!=' ')
14     {
15         cur.append(s.charAt(index++));
16     }
17     while(index < s.length() && s.charAt(index)==' ')
18         index++;
19     if(lastIndex == 0)
20         return helper(s,index).append(cur);
21     return helper(s,index).append(cur).append(' ');
22 }
23 }
原文地址:https://www.cnblogs.com/pkuYang/p/4330871.html