假设以下有一个结构体存放的是学生的记录，每条记录包括：学号、姓名、成绩

 1 #include <iostream>
 2 #include <string>
 3 
 4 using namespace std;
 5 
 6 struct Infor
 7 {
 8 public:
 9     int num;
10     string name;
11     int score;
12 };
13 
14 Infor find(Infor *a, int n, int num)
15 {
16     Infor result;
17     for (int i = 0; i < n; i++)
18     {
19         if (a[i].num == num)
20         {
21             result.name = a[i].name;
22             result.score = a[i].score;
23         }
24     }
25     return result;
26 }
27 
28 int main()
29 {
30     
31     Infor stu[4] = {
32         { 1024, "小甲鱼", 100 },
33         { 1026, "不知火舞", 60 },
34         { 1028, "黑夜", 40 },
35         { 1030, "迷途", 20 }
36     };
37 
38     Infor result = find(stu, 4,1028);
39     cout << result.name << "	" << result.score << endl;
40 
41     int u;
42     cin >> u;
43     return 0;
44 }