Valid Sudoku

Determine if a Sudoku is valid, according to: Sudoku Puzzles - The Rules.

The Sudoku board could be partially filled, where empty cells are filled with the character '.'.

A partially filled sudoku which is valid.

Note:
A valid Sudoku board (partially filled) is not necessarily solvable. Only the filled cells need to be validated.

代码不简洁，暴力解了。

class Solution {
public:
    bool isValidSudoku(vector<vector<char> > &board) {
        
        for(int i = 0 ; i < 9 ; i++)
        {
            map<char , int> m;
            for(int j = 0; j <9 ;j++)
            {
                char temp =board[i][j];
                //if((temp > '9' || temp <'0' )  && temp !='.')return 0;
                if(temp != '.')
                {
                    if(m.find(temp)!=m.end()) return 0;
                    else m[temp] = 1;
                }
                
            }
        }
        
        for(int i = 0 ; i < 9 ; i++)
        {
            map<char , int> m;
            for(int j = 0; j <9 ;j++)
            {
                char temp =board[j][i];
               // if((temp > '9' || temp <'0' )  && temp !='.')return 0;
                if(temp != '.')
                {
                    if(m.find(temp)!=m.end()) return 0;
                    else m[temp] = 1;
                }
                
            }
        }
        
        for(int i = 0 ; i < 3 ; i++)
        for(int j = 0 ; j < 3 ; j++)
        {
            map<char , int> m;
            for(int k = 0 ; k < 3; k++)
            {
                for(int l = 0 ; l < 3 ; l++)
                {
                    char temp = board[i*3+k][j*3+l];
                    //if((temp > '9' || temp <'0' )  && temp !='.')return 0;
                    if(temp != '.')
                    {
                        if(m.find(temp)!=m.end()) return 0;
                        else m[temp] = 1;
                    }
                }
            }
        }
        
        return 1;
        
    }
};