HDOJ.1228 A + B (map)

A + B

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题意分析

讲字符串和数字用map对应即可

代码总览

/*
    Title:HDOJ.1228
    Author:pengwill
    Date:2016-11-21
*/
#include <iostream>
#include <map>
#include <string>
using namespace std;
typedef map<string,int> mmp;
mmp p;
mmp::iterator iter1,iter2,iter3;

string s1,s2,s3,s4,s5,s6;
int main()
{
    cin.sync_with_stdio(false);
    cin.tie(0);
    p["zero"] = 0;
p["one"] = 1;
p["two"] = 2;
p["three"] = 3;
p["four"] = 4;
p["five"] = 5;
p["six"] = 6;
p["seven"] = 7;
p["eight"] = 8;
p["nine"] = 9;
    while(cin>>s1>>s2>>s3){
        if(s2.compare("+") == 0){
            if(s1.compare("zero")==0 && s3.compare("zero")==0){
                break;
            }else{
                cin>>s4;
                if(s4.compare("=") == 0){
                    iter1 = p.find(s1);iter2 = p.find(s3);
                    cout<<iter1->second + iter2->second<<endl;
                }else{
                    int a;
                    cin>>s5;
                    iter3 = p.find(s1);
                    iter1 = p.find(s3);iter2 = p.find(s4);
                    a = iter1->second * 10 + iter2->second;
                    cout<<a+ iter3->second <<endl;
                }

            }
        }else{
            int a,b;
            iter1 = p.find(s1);iter2 = p.find(s2);
            a = iter1->second * 10 + iter2->second;
            cin>>s1>>s2;
            if(s2.compare("=") == 0){
               // cout<<s2<<endl;
                iter3 = p.find(s1);
                b = iter3->second;
               // cout<<s1<<endl;
               // cout<<iter3->second<<endl;
                cout<<a + b<<endl;;
            }else{
                cin>>s3;
                iter1 = p.find(s1);iter2 = p.find(s2);
                b = iter1->second * 10 + iter2->second;
                cout<<a+b<<endl;
            }

        }
    }

    return 0;
}