Python二分查找

  1. 二分查找
  2. # _*_coding:utf-8_*_
    
    
    def list_number(in_list, number):
        s_number = 0
        d_number = len(in_list) - 1
        if number in in_list:
            while True:
                mid = (d_number + s_number) // 2
                if in_list[mid] == number:
                    return "数值%s在列表的第%s个" % (number, mid)
                elif in_list[mid] > number:
                    d_number = mid - 1
                elif in_list[mid] < number:
                    s_number = mid + 1
        else:
            print("没有该数值")
    
    
    if __name__ == '__main__':
        a = list((i + 2)*2 for i in range(14))
        print(a, len(a))
        while True:
            i = input(">>:")
            if i == "exit":
                break
            else:
                print(list_number(a, int(i)))
    
    
    
    [4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30] 14
    >>:14
    数值14在列表的第5个

  

原文地址:https://www.cnblogs.com/pengingintent/p/11097056.html