26. Remove Duplicates from Sorted Array

题目:

Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.

Do not allocate extra space for another array, you must do this in place with constant memory.

For example,
Given input array A = [1,1,2],

Your function should return length = 2, and A is now [1,2].

链接: http://leetcode.com/problems/remove-duplicates-from-sorted-array/

一刷

class Solution(object):
    def removeDuplicates(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        if len(nums) == 0:
            return 0
        distinct_count = 1
        prev = nums[0]
        for idx in range(1, len(nums)):
            if nums[idx] != prev:
                nums[distinct_count] = nums[idx]
                distinct_count += 1
                prev = nums[idx]
        return distinct_count

2/11/2017, Java

 1 public class Solution {
 2     public int removeDuplicates(int[] nums) {
 3         if (nums == null) return 0;
 4         if (nums.length == 1) return 1;
 5         int slow = 0;
 6         int fast = 1;
 7         
 8         while(fast < nums.length) {
 9             if (nums[slow] != nums[fast]) nums[++slow] = nums[fast];
10             fast++;
11         }
12         return slow + 1;
13     }
14 }
原文地址:https://www.cnblogs.com/panini/p/5569433.html