SQL求两个时间差

SELECTDATEDIFF( Second, '2009-8-25 12:15:12', '2009-9-1 7:18:20') --返回相差秒数
SELECTDATEDIFF( Minute, '2009-9-1 6:15:12', '2009-9-1 7:18:20') --返回相差分钟数
SELECTDATEDIFF( Day, '2009-8-25 12:15:12','2009-9-1 7:18:20')--返回相差的天数
SELECTDATEDIFF( Hour, '2009-8-25 12:15:12', '2009-9-1 7:18:20')--返回相差的小时
 
 
SELECTCONVERT(INT,DATEDIFF(Day, '2009-8-25 12:15:12', '2009-9-1 7:18:20')*24*60)+CONVERT(INT,DATEDIFF(Hour,'2009-8-25 12:15:12','2009-9-1 7:18:20')*60)+CONVERT(INT,DATEDIFF(Minute, '2009-9-1 6:15:12', '2009-9-1 7:18:20'))--求两个时间的相差的分钟数
原文地址:https://www.cnblogs.com/pancong/p/3037792.html