每一天都学习,每一天都会进步,假设你每一天进步0.001,一年之后的你
365*1.001
for i in range(365):
base = base * (1+0.001)
print(base)
print (pow(1.001,365))
##1.44
如果每天退步一点点
360*0.999
print (pow(0.999,365))
##0.025
周一到周五进步0.01,然后双休日退步0.01,怎么计算
dayup=0.01
daydown=-0.01
for i in range(365//7):
for i in range(5):
a = a * (1 + dayup)
for i in range(2):
a = a * (1 + daydown)
print(a)
周一到周五努力到什么程度才能 == 每天进步0.01结果一样
factory = 0.01for i in range(10000000):
base = 1
for i in range(365): # i=1周一
if i % 7 == 6:
base *= (1 - 0.01)
elif i % 7 == 0:
base *= (1 - 0.01)
else:
base *= (1 + factory)
if base > pow(1.01,365):
print(factory)
break
factory+=0.001
## factory = 1.9 所以平时要努力进步1.9才能够补回来