HashMap扩容-jdk1.9

1. threshold HashMap扩容阈值
    capacity(容量) * loadFactor(加载因子),如果new对象没有传入容量,则阈值大小为0,如果传入容量,则通过tableSizeFor 设置为大于容量的最小的2的幂次。

2. 扩容源码

 1 final Node<K,V>[] resize() {
 2         Node<K,V>[] oldTab = table;
 3         int oldCap = (oldTab == null) ? 0 : oldTab.length;
 4         int oldThr = threshold;
 5         int newCap, newThr = 0;
 6         //table 不为空
 7         if (oldCap > 0) {
 8             //无法扩容
 9             if (oldCap >= MAXIMUM_CAPACITY) {
10                 threshold = Integer.MAX_VALUE;
11                 return oldTab;
12             }//扩容2倍
13             else if ((newCap = oldCap << 1) < MAXIMUM_CAPACITY &&
14                      oldCap >= DEFAULT_INITIAL_CAPACITY)
15                 newThr = oldThr << 1; // double threshold
16         }
17         //以下table 为空情况
18         else if (oldThr > 0) //table 为空情况且 设置了初始大小initial capacity,新容量为阈值大小
19             newCap = oldThr;
20         else {               //table 为空情况且没有设置初始容量,采用默认值初始化
21             newCap = DEFAULT_INITIAL_CAPACITY;
22             newThr = (int)(DEFAULT_LOAD_FACTOR * DEFAULT_INITIAL_CAPACITY);
23         }
24         if (newThr == 0) {  //阈值
25             float ft = (float)newCap * loadFactor;
26             newThr = (newCap < MAXIMUM_CAPACITY && ft < (float)MAXIMUM_CAPACITY ?
27                       (int)ft : Integer.MAX_VALUE);
28         }
29         threshold = newThr;
30         @SuppressWarnings({"rawtypes","unchecked"})
31             Node<K,V>[] newTab = (Node<K,V>[])new Node[newCap];
32         table = newTab;
33         if (oldTab != null) {
34             for (int j = 0; j < oldCap; ++j) {
35                 Node<K,V> e;
36                 if ((e = oldTab[j]) != null) {
37                     oldTab[j] = null;
38                     //只有一个节点,直接放入新table中
39                     if (e.next == null)
40                         newTab[e.hash & (newCap - 1)] = e;
41                     //为红黑树,则对树进行拆分
42                     else if (e instanceof TreeNode)
43                         ((TreeNode<K,V>)e).split(this, newTab, j, oldCap);
44                     //链表拆分,原链表拆分成2个链表newTab[j],newTab[j + oldCap]为2个链表的头结点
45                     else { // preserve order
46                         Node<K,V> loHead = null, loTail = null;
47                         Node<K,V> hiHead = null, hiTail = null;
48                         Node<K,V> next;
49                         do {
50                             next = e.next;
51                             if ((e.hash & oldCap) == 0) {
52                                 if (loTail == null)
53                                     loHead = e;
54                                 else
55                                     loTail.next = e;
56                                 loTail = e;
57                             }
58                             else {
59                                 if (hiTail == null)
60                                     hiHead = e;
61                                 else
62                                     hiTail.next = e;
63                                 hiTail = e;
64                             }
65                         } while ((e = next) != null);
66                         if (loTail != null) {
67                             loTail.next = null;
68                             newTab[j] = loHead;
69                         }
70                         if (hiTail != null) {
71                             hiTail.next = null;
72                             newTab[j + oldCap] = hiHead;
73                         }
74                     }
75                 }
76             }
77         }
78         return newTab;
79     }

3.  由于扩容是比较耗性能的操作,所以一开始就尽量预测好初始容量,以减少扩容带来的性能损耗,比如 HashMap(1000),考虑变更为 new HashMap(1024) 但是不是最佳,因为加载因子默认0.75,即 

0.75*1000<1000,阈值小于1000,故最好设置为new HashMap(2048),就能避免resize

原文地址:https://www.cnblogs.com/oxf5deb3/p/13472815.html