一元多项式求导 (25)

 1 #include <iostream>
 2 using namespace std;
 3 
 4 int main()
 5 {
 6     int n, e;
 7     bool flag = false;
 8     while (cin >> n >> e)
 9     {
10         if (n*e)
11         {
12             if (flag)
13                 cout << " ";
14             cout << n*e << " " << e - 1;
15             flag = true;
16         }
17     }
18     if (!flag)
19         cout << "0 0" << endl;
20 
21     //system("pause");
22     return 0;
23 }
原文地址:https://www.cnblogs.com/ouyang_wsgwz/p/8529185.html