最大子数组之和(N)

 1 int maxSum(int *array, int n)
 2 {
 3     int rvsum = array[0];
 4     int newsum = 0;
 5 
 6     int i = 0;
 7     for(i = 0; i < n; i++) 
 8     {
 9         if(newsum >= 0)
10             newsum += array[i];
11         else    
12             newsum = array[i];
13 
14         if(rvsum < newsum) 
15             rvsum = newsum; 
16     }
17 
18     return rvsum;
19 }   
 1 //N^3
 2 int MaxSum(int *array, int n)
 3 {
 4     int maxinum = -INF; 
 5     int sum = 0;
 6     int i = 0, j = 0, k =0;
 7 
 8     for(i = 0; i < n; i++) 
 9     {
10         for(j = i; j < n; j++) 
11         {       
12             for(k = i; k<= j; k++) 
13             {       
14                 sum += array[k];
15             }       
16 
17             if(sum > maxinum)
18                 maxinum = sum;
19 
20             sum = 0;
21         }       
22     }
23 
24     return maxinum;                                                                                                
25 }
原文地址:https://www.cnblogs.com/openix/p/3165073.html