693. Binary Number with Alternating Bits

Question

693. Binary Number with Alternating Bits

Solution

思路:输入一个整数,它的二进制01交替出现,遍历其二进制字符串,下一个与上一个不等,返回true,如果有相等的就返回false

Java实现:

public boolean hasAlternatingBits(int n) {
    char last = '2'; // 非0非1即可
    for (char c : Integer.toBinaryString(n).toCharArray()) { // int转二进制字符串
        if (c == last) return false;
        last = c;
    }
    return true;
}