206、反转链表 | JS

给你单链表的头节点 head ,请你反转链表,并返回反转后的链表。
 

示例 1:


输入:head = [1,2,3,4,5]
输出:[5,4,3,2,1]
示例 2:

输入:head = [1,2]
输出:[2,1]
示例 3:

输入:head = []
输出:[]
 

提示:

链表中节点的数目范围是 [0, 5000]
-5000 <= Node.val <= 5000

题解:

双指针遍历,逐个反转。

 1 /**
 2  * Definition for singly-linked list.
 3  * function ListNode(val, next) {
 4  *     this.val = (val===undefined ? 0 : val)
 5  *     this.next = (next===undefined ? null : next)
 6  * }
 7  */
 8 /**
 9  * @param {ListNode} head
10  * @return {ListNode}
11  */
12 var reverseList = function(head) {
13     let p1 = head;
14     let p2 = null;
15     while(p1){
16         const tmp = p1.next;
17         p1.next = p2;
18         p2 = p1;
19         p1 = tmp;
20     }
21     return p2;
22 };
原文地址:https://www.cnblogs.com/oaoa/p/14679356.html