leetcode 175. Combine Two Tables

175. Combine Two Tables

Total Accepted: 16436 Total Submissions: 48308 Difficulty: Easy

Table: Person

+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| PersonId    | int     |
| FirstName   | varchar |
| LastName    | varchar |
+-------------+---------+
PersonId is the primary key column for this table.

Table: Address

+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| AddressId   | int     |
| PersonId    | int     |
| City        | varchar |
| State       | varchar |
+-------------+---------+
AddressId is the primary key column for this table.

Write a SQL query for a report that provides the following information for each person in the Person table, regardless if there is an address for each of those people:

FirstName, LastName, City, State

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1 # Write your MySQL query statement below
2 select FirstName, LastName, City, State from
3     Person left join Address
4         on Person.PersonId = Address.PersonId

LEFT JOIN

SQL LEFT JOIN 关键字

LEFT JOIN 关键字会从左表 (table_name1) 那里返回所有的行，即使在右表 (table_name2) 中没有匹配的行。

LEFT JOIN 关键字语法

SELECT column_name(s)
FROM table_name1
LEFT JOIN table_name2 
ON table_name1.column_name=table_name2.column_name

注释：在某些数据库中， LEFT JOIN 称为 LEFT OUTER JOIN。

原始的表 (用在例子中的)：

"Persons" 表：

Id_P	LastName	FirstName	Address	City
1	Adams	John	Oxford Street	London
2	Bush	George	Fifth Avenue	New York
3	Carter	Thomas	Changan Street	Beijing

"Orders" 表：

Id_O	OrderNo	Id_P
1	77895	3
2	44678	3
3	22456	1
4	24562	1
5	34764	65

左连接（LEFT JOIN）实例

现在，我们希望列出所有的人，以及他们的定购 - 如果有的话。

您可以使用下面的 SELECT 语句：

SELECT Persons.LastName, Persons.FirstName, Orders.OrderNo
FROM Persons
LEFT JOIN Orders
ON Persons.Id_P=Orders.Id_P
ORDER BY Persons.LastName

结果集：

LastName	FirstName	OrderNo
Adams	John	22456
Adams	John	24562
Carter	Thomas	77895
Carter	Thomas	44678
Bush	George

LEFT JOIN 关键字会从左表 (Persons) 那里返回所有的行，即使在右表 (Orders) 中没有匹配的行。